Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
Answer:
The mass of nitrogen molecule 
= 45.65 g
Explanation:
The equation for the redox reaction can be represented as follows:
We know that:
numbers of moles = mass/molar mass
For 
:
number of moles = 50g/92 g/mol
number of moles = 0.5435 mol
For 
:
number of moles = 45 g/ 32 g/mol
number of moles = 1.40625 mol
From the above equation;
number of moles of needed = 1/2 moles of = 1/2 × 1.40625 mol
= 0.703125 mol
The amount of present = 0.5435 moles which is less than the needed. As such is the limiting reagent
The number of moles of nitrogen molecule produced = 3 × ()
= 3 × 0.5435
= 1.6305 mol
The mass of nitrogen molecule = number of moles of × molar mass of
The mass of nitrogen molecule = 1.6305 mol × 28 g/mol
The mass of nitrogen molecule = 45.654 g
The mass of nitrogen molecule = 45.65 g
<span>No uses regarding the human body; it's a noble gas and does not react with anything.</span>
Answer:
0.26g of NaCl is the maximum mass that could be produced
Explanation:
Based on the reaction:
HCl + NaOH → NaCl + H₂O
<em>Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl</em>
<em />
To solve this question we need to find <em>limiting reactant. </em>The moles of limiting reactant = Moles of NaCl produced:
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl
<em>Moles NaOH -Molar mass: 40g/mol-:</em>
0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH
As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.
The mass of NaCl is:
<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>
0.0045 moles * (58.44g/mol) =
<h3>0.26g of NaCl is the maximum mass that could be produced</h3>
