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Aleonysh [2.5K]
4 years ago
10

What is the difference between boiling point and normal boiling point?​

Chemistry
1 answer:
Softa [21]4 years ago
5 0

Answer:

The boiling point is the temperature at which the vapor pressure equals the pressure of gas.

The normal boiling point is the temperature at which the vapor pressure equals one atmosphere

Explanation:

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The theory of continental drift was widely unaccepted until scientists started using ________ the map the ocean floor.
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B. SONAR (Sound Navigation Ranging)

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Use bond energies from Table 10.3 in the textbook to estimate the enthalpy change (ΔH) for the following reaction. C2H2(g)+H2(g)
Digiron [165]

Answer: =176.6kJmol^{-1}

Explanation:Bond energy of H-H is 436.4 kJ/mole

Bond energy of  C-H is 414 kJ/mol

Bond energy of C=C is 620 kJ/mol

Bond energy of C≡C is 835 kJ/mol

\Delta H= {\text {sum of bond energies of reactants}}-  {\text {sum of bond energies of products}}

\Delta H= {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}

\Delta H= {1B.E(835kJmole^{-1})+2B.E(414kJmole^{-1}) +1B.E(436.4kJmole^{-1})} -  {1B.E(620kJmole^{-1})+4B.E(414kjmole^{-1})}

=176.6kJmol^{-1}







7 0
4 years ago
Determine the name for aqueous H2CO3. carbonous acid dihydrogen carbonate carbonic acid hydrocarbonic acid hydrocarbide acid
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The name for aqueous H_{2} CO_{3} is carbonic acid.

So, option C is correct one.

Binary hydrogen compounds with non metals may form H+ (proton) and an anion dissolved in water. The acidic solutions are named as if they were molecular acids , using the usual name for the compound itself , replacing hydrogen with hydro- and suffix -ide with ic. The word acid is then use.

The inorganic acid is an acid drive from one or more inorganic compounds. All inorganic acids form hydrogen ions and the conjugate base ions when dissolved in water.

Example: carbonic acid ( H_{2} CO_{3} )

learn more about inorganic acid

brainly.com/question/15231908

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2 years ago
Much to everyone’s surprise, nitrogen monoxide (NO) has been found to act as a neurotransmitter. To prepare to study its effect,
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Answer: 0.0043mole

Explanation:Please see attachment for explanation

3 0
4 years ago
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