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3 years ago

(क) लेखक के मन में नदियों के प्रति कैसे भाव थे?नदियों से होने वाले प्रमुख दोलाभ लिखिए।

Chemistry

2 answers:

bija089 [108]3 years ago

5 0

Answer:

Yes this is true because I speak English

Levart [38]3 years ago

4 0

Lol.... too funny
Nope can’t read that at all.

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.500 mol of br2 and .500 mol of cl2 are placed in a .500L flask and allowed to reach equilibrium. at equilibrium the flask was f

Tasya [4]

Answer : The value of $K_c$ for the given reaction is, 0.36

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$Br_2(aq)+Cl_2(aq)\rightleftharpoons 2BrCl(aq)$

The expression of $K_c$ will be,

$K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}$

First we have to calculate the concentration of $Br_2,Cl_2\text{ and }BrCl$ .

$\text{Concentration of }Br_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M$

$\text{Concentration of }Cl_2=\frac{Moles}{Volume}=\frac{0.500mol}{0.500L}=1M$

$\text{Concentration of }BrCl=\frac{Moles}{Volume}=\frac{0.300mol}{0.500L}=0.6M$

Now we have to calculate the value of $K_c$ for the given reaction.

$K_c=\frac{[BrCl]^2}{[Br_2][Cl_2]}$

$K_c=\frac{(0.6)^2}{(1)\times (1)}$

$K_c=0.36$

Therefore, the value of $K_c$ for the given reaction is, 0.36

6 0

3 years ago

Read 2 more answers

Why is argon and chlorine both gases at room temperature?

vredina [299]

<span>Argon and chlorine are both gases at room temperature because they are non-metals.</span>

7 0

3 years ago

Помогите пожалуйста или с первым вопросом или со вторым. Буду очень благодарна, т.к. это мой зачет... :С

Bess [88]

Hsiaqoanwbwiso iDisks

5 0

3 years ago

The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?

Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

3 0

3 years ago

Mina is attending cooking school, where she prepares different mixtures of ingredients. She works with both homogenous and heter

rodikova [14]

Answer:

Honey is an homogeneous mixture

Salsa is an heterogeneous mixture

Explanation:

Honey is a sweet uniformly colored liquid that can be of a dark variety or of clear golden color. Honey is made in nature by bees from flower nectar and is used as a food additive or sweetener

Honey is a homogeneous mixture because the concentration of the components of honey are uniformly distributed throughout the mixture. Every portion has the same concentration of components

Salsa is a sauce made by mixing chopped tomatoes, onions, chilies, lime juice and seasoning and therefore consists of both solid and liquid components mixed in varying proportion such that part will have continuous that comes in between different types of solid and no two parts have exactly the same composition

Therefore, salsa is an heterogenous liquid.

3 0

3 years ago

(क) लेखक के मन में नदियों के प्रति कैसे भाव थे?नदियों से होने वाले प्रमुख दोलाभ लिखिए।​

(क) लेखक के मन में नदियों के प्रति कैसे भाव थे?नदियों से होने वाले प्रमुख दोलाभ लिखिए।