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12345 [234]
4 years ago
14

Walking without slipping requires a static friction force between your feet (or footwear) and the floor. As described in this ch

apter, the force on your foot as you push off the floor is forward while the force exerted by your foot on the floor is backward. what about your other foot, the one moved during a stride? What is the direction of the force on that foot as it comes into contact with the floor? Explain.
Physics
1 answer:
NeX [460]4 years ago
4 0

Answer:

Upward.

Explanation:

Frictional force will prevent you from slipping while walking on the floor. However for the other foot that is moved during a stride, there is a contact force. And the floor is exerting that contact force on the foot in the upward direction while foot exert it on the floor in downward direction when it comes in contact with the floor. That's how we balanced ourselves while walking, running etc. Contact force is also known as the normal force and this force exists wherever the two objects got into contact with other. It's example can be a book on a table, box on the floor, man standing on ground is due to contact force.

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A major process by which the Sun's energy is transported around the Earth system?
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Is it Conduction. Here's my theory e<span>nergy is transferred between the earth's surface and the atmosphere by Conduction, Convection and Radiation.</span>
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3 years ago
Which produces more energy? Nuclear fission or nuclear fission?
erastovalidia [21]

Answer:

Nuclear fission

Explanation:

your so very welcome

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3 years ago
A block of a plastic material floats in water with 42.9% of its volume under water. What is the density of the block in kg/m3?
adell [148]

To solve this problem we will apply the principle of buoyancy of Archimedes and the relationship given between density, mass and volume.

By balancing forces, the force of the weight must be counteracted by the buoyancy force, therefore

\sum F = 0

F_b -W = 0

F_b = W

F_b = mg

Here,

m = mass

g =Gravitational energy

The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore

\rho_w V_{displaced} g = mg

Remember the expression for which you can determine the relationship between mass, volume and density, in which

\rho = \frac{m}{V} \rightarrow m = V\rho

In this case the density would be that of the object, replacing

\rho_w V_{displaced} g = V\rho g

Since the displaced volume of water is 0.429 we will have to

\rho_w (0.429V) = V \rho

0.429\rho_w= \rho

The density of water under normal conditions is 1000kg / m ^ 3, so

0.429(1000) = \rho

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7 0
3 years ago
Compare and contrast the front limb bones of a human and a bat.
riadik2000 [5.3K]

Answer:

From the outside human arms, bird wings, and bats wings look very different. Humans are covered in skin, birds are covered in feathers, and bats are covered in hair. But on the inside there are many similarities among human, bird, and bat forearms. Did you know that humans, birds, and bats have the exact same types of bones in their forearm? These organisms share the same forearm bones because they all evolved from a common ancestor.

Human, bird, and bat forearm bones include the humerus, ulna, radius, carpals, metacarpals, and phalanges.

~i hope this helps~

5 0
3 years ago
Read 2 more answers
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.2 rad/s in 3.07 s. (a) f
Hitman42 [59]
(a) The angular acceleration of the wheel is given by
\alpha =  \frac{\omega_f - \omega_i }{t}
where \omega_i and \omega_f are the initial and final angular speed of the wheel, and t the time.

In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
\alpha =  \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
\theta (t) = \omega_i t +  \frac{1}{2} \alpha t^2
where \omega_i = 0 is the initial angular speed. So, the angle covered after a time t=3.07 s is
\theta=  \frac{1}{2}  \alpha t^2 =  \frac{1}{2}(3.65 rad/s^2)(3.07 s)^2 = 17.2 rad
6 0
3 years ago
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