Answer: 29.50 m
Explanation: In order to calculate the higher accelation to stop a train without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:
f=μ*N the friction force is equal to coefficient of static friction multiply the normal force (m*g).
f=m.a=μ*N= m*a= μ*m*g= m*a
then
a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2
With this value we can determine the short distance to stop the train
as follows:
x= vo*t- (a/2)* t^2
Vf=0= vo-a*t then t=vo/a
Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m
Acceleration of an object is depended upon the net force acting open the object and the mass of the object
The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k
Let r be the vector perpendicular to A and B,
r = A * B
A = 3i + 6j - 2k
B = 4i - j + 3k
a1 = 3
a2 = 6
a3 = - 2
b1 = 4
b2 = - 1
b3 = 3
a * b = ( a2 b3 - b2 a3 ) i + ( a3 b1 - b3 a1 ) j + ( a1 b2 - b1 a2 ) k
a * b = [ ( 6 * 3 ) - ( - 1 * - 2 ) ] i + [ ( - 2 * 4 ) - ( 3 * 3 ) ] j + [ ( 3 * - 1 ) - ( 4 * 6 ) ] k
a * b = 16 i - 17 j - 27 k
The perpendicular vector, r = 16 i - 17 j - 27 k
Therefore, the vector perpendicular to the plane of A = 3i + 6j - 2k and B = 4i - j + 3k is 16 i - 17 j - 27 k
To know more about perpendicular vectors
brainly.com/question/14384780
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Centripetal acceleration is (speed-squared) / (radius)
CA = (6 m/s)² / (9 m)
CA = (36 m²/s²) / (9 m)
CA = (36/9) (m²/m·s²)
<em>Centripetal acceleration = 4 m/s²</em>
Average velocity =
(displacement) / (time for the displacement)
and
(direction of the displacement) .
Displacement =
(distance from the start-point to the end-point)
and
(direction from the start-point to the end-point) .
When Ben is 200 meters from the corner store,
he is (500 - 200) = 300 meters from his house.
His displacement is
300 meters in the direction
from his house to the neighbor .
His average velocity is
(300/910) = 0.33 meters per second, in the
direction from his house to the neighbor .
