A friend throws a baseball horizontally. He releases it at a height of 2.0 m and it lands 21 m from his front foot, which is dir

Question

4 years ago

8

ectly below the point at which he released the baseball. (a) How long was it in the air? (b) How fast did he throw it?

1 answer:

dangina [55] · Answer 1 · 2022-01-05T01:48:06+03:00

Answer:

<h2>a) The base baseball was in air for 0.64 seconds.</h2><h2>b) Speed of throwing is 32.89 m/s</h2>

Explanation:

a)Consider the vertical motion of baseball

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 9.81 m/s²

Time, t = ?

Displacement, s = 2 m

Substituting

s = ut + 0.5 at²

2 = 0 x t + 0.5 x 9.81 x t²

t = 0.64 seconds

The base baseball was in air for 0.64 seconds.

b)Consider the horizontal motion of baseball

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = ?

Acceleration, a = 0 m/s²

Time, t = 0.64 s

Displacement, s= 21 m

Substituting

s = ut + 0.5 at²

21 = u x 0.64 + 0.5 x 0 x 0.64²

u = 32.89 m/s

Speed of throwing is 32.89 m/s