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Sonbull [250]
3 years ago
6

If a 8.0 kg mass is hung on the end of a spring, it is stretched 0.78 meters as a result. What is the force constant of the spri

ng?
Physics
2 answers:
Alborosie3 years ago
3 0

Answer:

K=100.62N/m

Explanation:

Given:

             m= 8.0 Kg\\x=0.78 m

We know from Hook's law

           F= k x

where

           F= m g

So equating we get

             mg=kx\\k=\frac{mg}{x} \\k=\frac{8*9.8}{0.78}\\k=100.62 N/m

Hatshy [7]3 years ago
3 0

Answer:

k=100.5 n/m

Explanation:

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