Question

If a 8.0 kg mass is hung on the end of a spring, it is stretched 0.78 meters as a result. What is the force constant of the spring?

Answer 1

Answer:

$K=100.62N/m$

Explanation:

Given:

             $m= 8.0 Kg\\x=0.78 m$

We know from Hook's law

           $F= k x$

where

           $F= m g$

So equating we get

             $mg=kx\\k=\frac{mg}{x} \\k=\frac{8*9.8}{0.78}\\k=100.62 N/m$

Answer 2

Answer:

k=100.5 n/m

Explanation: