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Georgia [21]
3 years ago
8

Which statement best describes the movement of electrical current when a capacitor is used in a circuit?

Physics
1 answer:
Masteriza [31]3 years ago
4 0

Answer: B.

Capacitors prevent current from moving through a circuit 

Explanation:

If a direct voltage is applied on the capacitor, no conduction current flows through the capacitor if its insulating medium is perfect insulator. This is due to the fact that there are no free charge carriers in such medium. Basically the real insulator contains very few charge carriers and therefore a very small leakage current passes in the capacitor depending on the conductivity of the insulator.

If an alternating voltage is applied on the capacitor, a displacement current passes through the capacitor irrespective of the insulating medium. This current is termed also the capacitive current. It flows because of changing electric displacement with time.

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What row of the periodic table does this element belong?
sladkih [1.3K]

Answer:

Group 18

Explanation:

This element has a full octet, therefore it is a noble gas, being in period 18. (I think its Argon if you need that too)

Hope that helps

3 0
3 years ago
The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni
Marina CMI [18]

Answer:

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = \frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}

Q = \frac{9\times16^2\times10^{-2}}{9\times10^9}

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

5 0
3 years ago
A marble runs off the edge of a table that is 1.5 m high and the marble lands 0.50 m from the base of the table. a. How much tim
Free_Kalibri [48]

Answer:

t = 0.55[sg]; v = 0.9[m/s]

Explanation:

In order to solve this problem we must establish the initial conditions with which we can work.

y = initial elevation = - 1.5 [m]

x = landing distance = 0.5 [m]

We set "y" with a negative value, as this height is below the table level.

in the following equation (vy)o is equal to zero because there is no velocity in the y component.

therefore:

y = (v_{y})_{o}*t - \frac{1}{2} *g*t^{2}\\   where:\\(v_{y})_{o}=0[m/s]\\t = time [sg]\\g = gravity = 9.81[\frac{m}{s^{2}}]\\ -1.5 = 0*t -4.905*t^{2} \\t = \sqrt{\frac{1.5}{4.905} } \\t=0.55[s]

Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.

(v_{x} )_{o} = \frac{x}{t} \\(v_{x} )_{o} = \frac{0.5}{0.55} \\(v_{x} )_{o} =0.9[m/s]

3 0
3 years ago
A spring has a spring constant of 65.5 N/m and it is
iren [92.7K]
0.234m !!!!!! hope this helps :)))
8 0
3 years ago
iv. An object is 14 cm in front of a convex mirror. The image is 5.8 cm behind the mirror. What is the focal length of the mirro
Dvinal [7]

Answer:

C. 9.9 cm

Explanation:

The location of the object, u = 14 cm

The location of the image, v = 5.8 cm

The focal length of the mirror, f = Required

The mirror formula for a convex mirror is given as follows;

\dfrac{1}{u} -\dfrac{1}{v} = -\dfrac{1}{f}

Therefore, we get;

\dfrac{1}{14 \ cm} -\dfrac{1}{5.8 \ cm} =- \dfrac{41}{406 \ cm} = -\dfrac{1}{f}

Therefore;

f = \dfrac{406 \ cm}{41}  \approx 9.9 \ cm

The focal length of the mirror, f ≈ 9.9 cm

6 0
3 years ago
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