Answer:
The mass of 0.100 mole of neon is 2.018 grams.
Explanation:
As we know the formula to find mass:
Number of moles = Mass/ Molar mass
0.100 = Mass/ 20.17
0.100 x 20.17 = Mass
Mass=2.018 grams.
Hope it helps!
Answer:
4.77 is the pH of the given buffer .
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=-\log[K_a]+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BK_a%5D%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=-\log[K_a]+\log(\frac{[CH_3CH_2COONa]}{[CH_3CH_2COOH]})](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BK_a%5D%2B%5Clog%28%5Cfrac%7B%5BCH_3CH_2COONa%5D%7D%7B%5BCH_3CH_2COOH%5D%7D%29)
We are given:
= Dissociation constant of propanoic acid = 
![[CH_3CH_2COONa]=0.254 M](https://tex.z-dn.net/?f=%5BCH_3CH_2COONa%5D%3D0.254%20M)
![[CH_3CH_2COOH]=0.329 M](https://tex.z-dn.net/?f=%5BCH_3CH_2COOH%5D%3D0.329%20M)
pH = ?
Putting values in above equation, we get:
![pH=-\log[1.3\times 10^{-5}]+\log(\frac{[0.254 M]}{[0.329]})](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B1.3%5Ctimes%2010%5E%7B-5%7D%5D%2B%5Clog%28%5Cfrac%7B%5B0.254%20M%5D%7D%7B%5B0.329%5D%7D%29)
pH = 4.77
4.77 is the pH of the given buffer .
To solve this problem, let us first understand what does
mega meters mean. Now by definition, mega means a factor of one million which
is a unit prefix in Metric Systems of units. It is denoted by the unit symbol
M.
So for example if we have a mega of something, it means a
million of something. So in this case, if we have 1 mega meter, what it means
is 1 million meter, which is written as:
1 mega meter = 1,000,000 meter
To show the decimal points:
1.0 mega meter = 1,000,000.0 meter
So we see that the decimal point move 6 zeroes to the
right, therefore the direction is to the right.
Answer:
<span>6 places to the right</span>
10 electrons will occupy the five orbitals in the atoms d sub shell like this. Each electron fills one by one in each orbital. So first 1 electron will fill the first orbital, then the second will move on to the next and so on. So for example…if there were 7 electrons, the first two sub shells would be filled, and the other three would have one electron each