There is an increase in the number of collisions between particles and the walls of the container<span>. b. There is an increase in the </span>temperature of the gas. If<span> the volume of a </span>container<span> of </span>gas<span> is reduced, what will </span>happen to the pressure inside<span> the </span>container
Answer:
<h3>The answer is 526.32 mL</h3>
Explanation:
To find the original volume we use the formula for Boyle's law which is
Since we are finding the original volume
From the question we have
We have the final answer as
<h3>526.32 mL</h3>
Hope this helps you
In the reaction given, 3.07 moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide.
<h3>STOICHIOMETRY:</h3>
According to this question, the following balanced equation is given:
2C6H14 + 19O2 → 12CO2 + 14H2O
Based on the above equation, 2 moles of hexane (C6H14) is burnt in oxygen to produce 12 moles of carbon dioxide (CO2).
This means that for 18.4 moles of carbon dioxide to be formed, (18.4 × 2)/12 = 3.07 moles of hexane must burn.
Therefore, 3.07 moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide.
Learn more about stoichiometry at: brainly.com/question/9743981
Answer:
Explanation:
Givens
v1 = 375 cm^3
P1 = 770 mm Hg
V2 = ?
P2 = 750 mm Hg
Formula
V1 P1 = V2 P2
Solution
375 * 770 = V2 * 750 Combine the left
288750 = V2 * 750 Divide both sides by 750
288750/750 = V2
V2 = 385
