To be floating, the gravity force of the iceberg should be same as the buoyancy force that result from the difference of the ice and water density.
The density of ice is 920 and water is 1030, then the difference should be: 1030kg/m3-920kg/m3= 110kg/m3
Let say that the volume of ice below the water is volume1 and the volume above the water(exposed volume) is volume2.
You can get this equation
volume1+volume2= 100%
volume1= 100%- volume2
Insert it into the buoyancy and gravity force will result
buoyancy=gravity
110kg/m3*volume1= 920kg/m3 *volume2
110kg/m3*(100%- volume2)= 920kg/m3 *volume2
110kg/m3 - 110kg/m3*volume2= 920kg/m3 *volume2
110kg/m3 = 1030kg/m3 *volume2
volume2= 110/1030= 0.1067= 10.7%
Which elements are most reactive?
The alkali metals, found in group 1 of the periodic table (formerly known as group IA), are very reactive metals that do not occur freely in nature. These metals have only one electron in their outer shell. Therefore, they are ready to lose that one electron in ionic bonding with other elements.
Fluorine is the most reactive
Answer:
hope this helps you
Explanation:
Example 1: A 20 kg object has a velocity of 4.5 m/s in the positive x direction. ... What is the momentum of a 3000 kg truck traveling at 25 m/s? 2. A 1500 kg ferryboat has a momentum of 25000 kg∙m/s. ... *A 0.01 kg bullet has a speed of 700 m/s before it strikes a 0.95 kg wooden block ... We will be going outside so please.
Answer : The concentration after 17.0 minutes will be, 
Explanation :
The expression for first order reaction is:
![[C_t]=[C_o]e^{-kt}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%5BC_o%5De%5E%7B-kt%7D)
where,
= concentration at time 't' (final) = ?
= concentration at time '0' (initial) = 0.100 M
k = rate constant = 
t = time = 17.0 min = 1020 s (1 min = 60 s)
Now put all the given values in the above expression, we get:
![[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%280.100%29%5Ctimes%20e%5E%7B-%285.40%5Ctimes%2010%5E%7B-3%7D%29%5Ctimes%20%281020%29%7D)
![[C_t]=4.05\times 10^{-4}M](https://tex.z-dn.net/?f=%5BC_t%5D%3D4.05%5Ctimes%2010%5E%7B-4%7DM)
Thus, the concentration after 17.0 minutes will be, 