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Greeley [361]
3 years ago
5

A 1.00 l sample of water contains 0.0036 g of cl- ions. determine the concentration of chloride ions in ppm if the density of th

e solution is 1.00 g/ml
Chemistry
1 answer:
Illusion [34]3 years ago
6 0
Parts-per-million is a form of concentration that is confusing to some. It is often used for aqueous solutions at low concentrations because, as you state in your question, in dilute solutions the density of water has not been affected ie. is still 1.00 g/mL.

parts per million is defined as micrograms of solute per milliliter of solution. This doesn't inherently make sense since micrograms are on the millionths scale, but mL are on the thousandth scale, so it would seem to be millionth per thousandth--Not so! Since the 1.00 mL of water weighs 1.00 g, ug/mL converts, for dilute aqueous solutions, to ug/g, which now makes sense as parts per million. So, from the information given, the calculation is quite simple:

0.0036 g Cl * 10^6 ug/1 g = 3600 ug Cl

1.00 L * 1000 mL/1L = 1000 mL

Concentration of Cl- in solution in ppm:

3600 ug Cl- / 1000 mL = 3.6 ppm Cl-
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A gas at constant temperature has a pressure of 404.6 kPa with a volume of 12 ml. If the volume changes to 43ml, what is the new
blagie [28]

Answer:

The answer is

<h2>112.912 kPa</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

404.6 kPa = 404600 Pa

From the question we have

P_2 =  \frac{404600 \times 12}{43}  =  \frac{4855200}{43}  \\  = 112911.6279... \\  = 112912

We have the final answer as

<h3>112.912 kPa</h3>

Hope this helps you

4 0
3 years ago
Will give brainliest!!!!
Luda [366]
The answer is aldehyde
4 0
3 years ago
Which equations shows the complete dissociation of a strong base?
tensa zangetsu [6.8K]
The correct answer is the fourth option. The complete dissociation of a strong base is BOH + h20 -> B+ + OH- + H20 since this is the only base from the choices given. A base is a substance that accepts hydrogen ions. 
4 0
3 years ago
What is the correct classification of a mixture in which both a solid and liquid are visible?
Setler [38]

The answer is D.

"a heterogeneous mixture and a suspension"

6 0
3 years ago
You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.6 m. (a) what fraction of its initial energy is los
sweet [91]

Answer : Part a) Fraction of energy lost : 20 %

Part b) Speed before and after bounce = 6.3 m/s and 5.6 m/s

Part c) Energy is lost as thermal energy .

Part A) Fraction of energy lost during bouncing :

The energy possessed by any object when present at any height is potential energy . The formula of potential energy is given as :

PE = mgh

where PE = potential energy

,m = mass pf object , g = gravitational acceleration and h = height

Given : Initial height , h₁ = 2 m final height , h₂ = 1.6 m

Initial potential energy : m * g* h ₁

Final potential energy = m* g* h₂

Energy lost = Initial PE - Final PE

= ( mgh₁ - mgh2 )

Fraction of energy lost : \frac{energy lost}{initial energy}=\frac{mgh1 - mgh2}{mgh1}

Plugging value in above formula and taking " mg " common =>

Fraction of energy lost = \frac{mg(h1-h2)}{mg (h1)} * 100

= \frac{(h1-h2)}{h1}  * 100

= \frac{(2 - 1.6) }{2}  * 100

Fraction of energy lost = 20%

---------------------------------------------------------------------------------------------------

Part B ) Speed of ball just before and after the bounce.

Speed of ball before the bounce :

The potential energy gets converted to kinetic energy when it fall from height of 2m , so

Potential energy = kinetic energy

mgh₁ = \frac{1}{2} m v²

or v ² = 2gh₁

Given : g = 9.8 m/s² h= 2 m

v² = 2 * 9.8 m/s² * 2 m = 39.2 m²/s²

v = 6.3 m/s

Speed of ball after bounce :

Potential energy = kinetic energy

mgh₂ = \frac{1}{2} m v²

or v² = 2gh₂

= 2 * 9.8 m/s² * 1.6 m = 31.36 m²/s²

v = 5.6 m/s

---------------------------------------------------------------------------------------------

Part C) The energy lost due to friction. When the ball touches the ground , there occur friction force between the surface of ground and ball , due to which energy is lost as thermal energy .

5 0
3 years ago
Read 2 more answers
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