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Greeley [361]
3 years ago
5

A 1.00 l sample of water contains 0.0036 g of cl- ions. determine the concentration of chloride ions in ppm if the density of th

e solution is 1.00 g/ml
Chemistry
1 answer:
Illusion [34]3 years ago
6 0
Parts-per-million is a form of concentration that is confusing to some. It is often used for aqueous solutions at low concentrations because, as you state in your question, in dilute solutions the density of water has not been affected ie. is still 1.00 g/mL.

parts per million is defined as micrograms of solute per milliliter of solution. This doesn't inherently make sense since micrograms are on the millionths scale, but mL are on the thousandth scale, so it would seem to be millionth per thousandth--Not so! Since the 1.00 mL of water weighs 1.00 g, ug/mL converts, for dilute aqueous solutions, to ug/g, which now makes sense as parts per million. So, from the information given, the calculation is quite simple:

0.0036 g Cl * 10^6 ug/1 g = 3600 ug Cl

1.00 L * 1000 mL/1L = 1000 mL

Concentration of Cl- in solution in ppm:

3600 ug Cl- / 1000 mL = 3.6 ppm Cl-
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What type of radioactive decay will the isotopes 13B and 188Au most likely undergo?
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Answer:

b. Beta emission, beta emission

Explanation:

A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).

Now let us look at the N/P ratio of each atom;

For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6

For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4

For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.

For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.

8 0
2 years ago
Sucralfate (molecular weight: 2087 g/mol) is a major component of Carafate®, which is prescribed for the treatment of gastrointe
dybincka [34]

Answer:

Option b. 0.048 M

Explanation:

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1 g . 1 mol / 2087 g = 4.79×10⁻⁴ moles.

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Let's convert the volume of solution in L

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3 0
3 years ago
How can you explain what happened?
galina1969 [7]

Answer:

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Explanation:

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3 0
2 years ago
How much would the temperature of 275 g of water increase if 36.5 kj of heat were added?
Andrew [12]

<u>Answer:</u> The temperature increase will be 31.70°C.

<u>Explanation:</u>

To calculate the increase in the temperature of the system, we use the equation:

q=mc\Delta T

where,

q = Heat absorbed = 36.5 kJ = 36500J

m = Mass of water = 275 g

c = Specific heat capacity of water = 4.186J/g^oC

\Delta T = change in temperature = ? °C

Putting values in above equation, we get:

36500J=275\times 4.186J/g^oC\times \Delta T\\\\\Delta T=31.70^oC

Hence, the temperature increase will be 31.70°C.

8 0
2 years ago
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Natasha_Volkova [10]

Answer:

C . A person lifting a weight

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3 years ago
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