Molecules are made up by chemically bonding two or more atoms of the same element or different elements, they don’t have charge, and the atoms are bonded by covalent bonds. <span>Lattices have a three- dimensional ordered arrangement of basic units (that can be an atom, molecule or an ion). Lattices are crystalline structures with these repeated basic units. When ions joined with ionic bonds, they form ionic crystals. The formula unit tells us that aluminium hydroxide has a crystal structure made from molecules. </span>
        
                    
             
        
        
        
Answer:
9 : 8
Explanation:
Aluminum oxide has the following formula Al₂O₃. 
Next, we shall determine the mass of Al and O₂ in Al₂O₃. This can be obtained as follow:
Mass of Al in Al₂O₃ = 2 × 27 = 54 g
Mass of O₂ in Al₂O₃ = 3 × 16 = 48 g
Finally, we shall determine the mass ratio of Al and O₂. This can be obtained as follow:
Mass of Al = 54 g
Mass of O₂ = 48 g
Mass of Al : Mass of O₂ = 54 : 48
Mass of Al : Mass of O₂ = 54 / 48
Mass of Al : Mass of O₂ = 9 / 8
Mass of Al : Mass of O₂ = 9 : 8
Therefore, the mass ratio of Al and O₂ in Al₂O₃ is 9 : 8
 
        
             
        
        
        
In order to calculate how much heat is needed to raise the temperature you need to use the formula q =mass x specific heat x (final temperature- initial temperature) where q represents heat being absorbed or released. Before you begin you would convert kg to g because the specific heat is measure in g. So you would set up the equation as q = 358 g x .092 x (60-23 degrees Celsius) which would give you 1218.6
        
                    
             
        
        
        
Answer:
Q= mc∆T(ice) + mLF(ice) + mc∆T(water) + mLV(water) + mc∆T(steam) 
m=250 g = 0.25 kg = ¼ kg c(ice)= 2100 J/kg.K c(water)= 4200 J/kg.K LF(ice)= 333.7 kJ/kg LV(water)= 2256 kJ/kg c(steam)= 2080 J/kg.K
Explanation:
Q= ¼ × 2100 × (0°-(-30°)) + ¼ × 333700 + ¼ × 4200 × (100°-0°) + ¼ × 2256000 + ¼ × 2080 × (145°-100°) 
Q= 15750 + 83425 + 105000 + 564000 + 23400 
Q= 791575 J
 
        
             
        
        
        
Answer:
B
B
A
C
Explanation:
3
B. Vanillin as a phenoxide ion (conjugate base) 
4
B. Protonation of acetic anhydride
5
A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride 
6
C. 1 mmol of vanillin and 10.6 mmol acetic anhydride