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3 years ago

Dissolved minerals trapped in magma under tremendous pressure provide the force for a volcanic eruption.

Chemistry

2 answers:

dmitriy555 [2]3 years ago

7 0

Not so. Dissolved gases trapped in the minerals provide the pressure for an explosive eruption.

e-lub [12.9K]3 years ago

4 0

The given statement is false.

As it is the dissolved gases, not the dissolved minerals, which are trapped in magma under tremendous pressure that provide the force for a volcanic eruption. The magma comprises dissolved gases that offers the driving force, which makes the majority of volcanic eruptions.

As magma reaches towards the surface and the pressure reduces, the gases get discharged from the liquid part of the magma and continue to move upward and finally get discharged into the atmosphere.

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How many Ne atoms are contained in 32.0 g of the element?

Svetlanka [38]

Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

1 mole=6.022*10²³ particles (atoms or molecules)

Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.

3 0

3 years ago

How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0. °C? Group

OlgaM077 [116]

Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

P= 1.00 atm
V= 150 L
n= ?
R= 0.082 $\frac{atm*L}{mol*K}$
T= 0 C= 273 K

Replacing:

1.00 atm* 150 L= n*0.08206 $\frac{atm*L}{mol*K}$ *273 K

Solving:

$n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}$

n= 6.69 moles

Being Cl= 35.45 g/mole, the molar mass of chlorine gas is:

Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

$mass=\frac{6.69 moles*70.9 grams}{1 mole}$

mass= 474.321 grams ≅ 474 grams

<u><em>474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C</em></u>

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3 years ago

What is the difference between a gas and a solid

Yuliya22 [10]

A gas can move around freely while a solid is hard and can’t move around freely

7 0

3 years ago

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Basile [38]

Answer:

An element that is oxidized is a reducing agent, because the element loses electrons, and an element that is reduced is an oxidizing agent, because the element gains electrons.

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3 years ago

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An equilibrium mixture of O2, SO2 and SO3 contains equal concentrations of SO2 and SO3.

AleksAgata [21]

Answer:

[O₂(g)] = 0.0037M

Explanation:

2SO₂(g) + O₂(g) => 2SO₃(g)

Conc: [SO₂(g)] [O₂(g)] [SO₃(g)] and [SO₂(g)] = [SO₃(g)]

Kc = [SO₃(g)]²/[O₂(g)][SO₂(g)]² => Kc = 1/[O₂(g)] = 270 if [SO₂(g)] = [SO₃(g)]

∴ [O₂(g)] = (1/270)M = 0.0037M

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3 years ago