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3 years ago

What's the average atomic mass of bromine and state which isotope is more abundant?

Chemistry

1 answer:

sasho [114]3 years ago

3 0

The answer would be Br-79 because it is 50.69% abundant.
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You might be interested in

specify whether each of the items listed is hydrophilic or hydrophobic by dragging the labels into the appropriate box.

erik [133]

Hydrophilic;

Polar compounds

water

ions

glucose

Hydrophobic;

Triglycerides

cholesterol

Lipids

Oil

Carbohydrates

<h3>What are hydrophilic substances?</h3>

The term hydrophilic substances is used to describe the substances that could dissolve in water. They are those substances that are water soluble. Somehow, the substances must be polar because in chemistry like dissolves like.

The hydrophobic substances are those substances that do not dissolve in water. They are nonpolar and interact with other nonpolar substances.

The classification of the substances took place below;

Hydrophilic;

Polar compounds

water

ions

glucose

Hydrophobic;

Triglycerides

cholesterol

Lipids

Oil

Carbohydrates

Learn more about hydrophilic substances:brainly.com/question/4692308

#SPJ1

4 0

1 year ago

What is the concentration of a solution containing 1.11 g sugar (sucrose, C12H22O11, MW = 342.3 g/mol, d = 1.587 g/cm3) in 432 m

djyliett [7]

Answer:

0.0075 M

0.0060 m

Explanation:

Our strategy here is to use the definition of molarity and molality to solve this question.

The molarity is the number of moles of solute, sucrose in this case, per liter of solution.

The molality is the number of moles of solute per kilogram of solvent.

So the molarity of the solution is

M = moles of solute/ V solution

As we see we need the volume of solution since we are only given the volume of solvent, but this will be easy to compute since we have the density of sucrose.

So determine the moles of sucrose , and the volume of solution:

Moles sucrose = 1.11 g/342.3 g/mol = 3.24 x 10⁻³ M

Volume of solution = Vol Sucrose + Vol glycerine

d = m/V ⇒ Vsucrose = m / d = 1.11 g/ 1.587 g/cm³ = 0.70 cm³

Vol solution = 432 mL + 0.70 mL = 432.7 mL (1cm³ = 1 mL)

Vol solution = 432.7 mL x 1 L / 1000 mL = 0.4327 L

⇒ M = 3.2 x 10⁻³ mol / 0.4327 L = 0.0075 M

For the molarity what we need is to first calculate the kilograms of glycerine from the given density:

d = m/v ⇒ m = d x v = 1.261 g/cm³ x 432 cm³ = 544.75 g

Converting to Kg:

544.75 g x 1 Kg/ 1000 g = 0.544 kg

Now the molality is

m = mol sucrose/ kg solvent = 3.24 x 10⁻³ mol / 0.544 Kg = 0.0060 m

Note: In the calculation for volume of solution we could have approximated it to that of just glycerine, but since the density of sucrose was given we calculated the total volume of solution to be more rigorous.

8 0

3 years ago

Which allotrope of carbon is the most malleable?

Leni [432]

The answer is: Graphite

8 0

2 years ago

How many hydrogen atoms are in 5 molecules of isopropyl alcohol

pychu [463]

You have to double them

5 0

3 years ago

How do you calculate the relative formula mass of a compound

RSB [31]

Write the formula of the compound.
Write the numbers of each atom in the formula. Insert the relative atomic mass for each type of atom. Calculate the total mass for each element.
Add up the total mass for the compound.

7 0

2 years ago