Answer:
a) Helicopter need to drop the supply after 3.46 seconds.
b) Helicopter need to drop the supply after 1.83 seconds.
Explanation:
a) Let us find time of flight of supplies that is vertical motion of supplies,
We have equation of motion s = ut + 0.5at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 80 m
Substituting,
s = ut + 0.5 at²
80 = 0 x t + 0.5 x 9.81 x t²
t = 4.04 s
Distance traveled by helicopter in 4.04 seconds at 40 m/s = 4.04 x 40 = 161.54 m
Distance helicopter can fly without dropping supply = 300 - 161.54 = 138.46 m
Time taken for this
So helicopter need to drop the supply after 3.46 seconds.
b) Speed of truck = 25 mi/h = 11.11 m/s westward
Speed of helicopter = 40 m/s eastward
Relative velocity, = 40 + 11.11 = 51.11 m/s
We have equation of motion s = ut + 0.5at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 80 m
Substituting,
s = ut + 0.5 at²
80 = 0 x t + 0.5 x 9.81 x t²
t = 4.04 s
Distance traveled by relative bodies in 4.04 seconds at 51.11 m/s = 4.04 x 51.11 = 206.48 m
Distance helicopter can fly without dropping supply = 300 - 206.48 = 93.52 m
Time taken for this
So helicopter need to drop the supply after 1.83 seconds.