<span>a. n/4 ≤ -1
Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.
That in the real number line is all the numbers to the left of - 4 (including -4)
The matching graph is the B.
b. -10n ≥ -100
Divide both sides by - 10 => n ≤ 10
That is all the real numbers less or equal than 10.
In the real number line it is all the numbers to the left of 10, including 10.
So, the matching graph is the A.
c. 5x ≥ 20
Divide both sides by 5 => x ≥ 4
That is all the real numbers greater or equal to 4.
In the real number line it is all the numbers to the right of 4, including 4.
The matching graph is C.</span>
Answer:
2
Step-by-step explanation:
For any positive numbers a,b we always have the following identity:

(gcd(a,b) denotes the greatest common divisor between a and b, and lcm(a,b) denotes the least common multiple between a and b)
In our case, we are given that
and that
. Plugging that in into our identity, we get:

And so solving for
:

Answer:
LCM = 30
Step-by-step explanation:
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Answer: Choice B
The slope is rise/run = 2/3 meaning we go up 2 and over to the right 3. For instance, moving from (0,0) to (3,2) has us move up 2 and over to the right 3.
Alternatively you can use the slope formula m = (y2-y1)/(x2-x1) to get the same result of 2/3.