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Mariulka [41]
3 years ago
9

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the in

dex of refraction? A. 1.06 B. 0.944 C. 0.827 D. 1.21
Physics
1 answer:
finlep [7]3 years ago
4 0

Explanation:

It is given that,

Angle of incidence from air to another medium, i = 26°

The angle of reflection, r = 32°

We need to find the refractive index of the medium. The ratio of sine of angle of incidence to the sine of angle of reflection is called refractive index. It can be given by :

n=\dfrac{\sin i}{\sin r}\\\\n=\dfrac{\sin (26)}{\sin (32)}\\\\n=0.82

So, the index of refraction is 0.82. Hence, the correct option is C.

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an astronaut on an eva has wandered dangerously far away from the shuttle. she has also exhausted all the fuel in her jet pack.
V125BC [204]

The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:

  • Throwing the thruster away from the ship.

The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum  is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.

Initial instant. Astronaut and thrust together.

        p₀ = 0

Final moment. The astronaut now the thruster in the opposite direction of the ship.

       m_f = m v + M v '

where m is propellant mass and M the astronaut mass.

As the moment is preserved.

       0 = m v + M v ’

      v ’= - \frac{m}{M} \ v  

We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.

The magnitude of the velocity is given by the relationship between the masses.

In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:

  • Throwing the thruster away from the ship.

Learn more here:  brainly.com/question/14798485

5 0
2 years ago
Which month has the longest day and shortest night?
Volgvan
I think it’s June 20
8 0
3 years ago
An experiment is performed on an unknown material and produces the given heat curve. The temperature of the material is shown as
BlackZzzverrR [31]

Answer:

In the table, 1=46.7 °C, 1=165 J, 2=819 J, 3=1510 J, and 4=2830 J.

Other experiments determine that the material has a temperature of fusion of

fusion =235 °C and a temperature of vaporization of vapor=481 °C.

If the sample of material has a mass of =8.60 g, calculate the specific heat when this material is a solid, and when it is liquid, l

4 0
3 years ago
A positive force on the balance indicates a downward force on the silver sphere while a negative force on the balance indicates
anastassius [24]

The two spheres have opposite charges.

<h3 /><h3 /><h3>What are types charge?</h3>
  • A charge can be negatively charged or positively charged.
  • When two charges have opposite signs, that is positive and negative signs, the two charges will attract each other.
  • When the two charges have the same sign, it causes repulsion.

When a positive charge points downwards ↓ and the negative charge points upwards ↑, this causes attraction and shows that the two charges are different.

Thus, we can conclude that the two spheres have opposite charges.

Learn more about attraction and repulsion of charges here: brainly.com/question/2396080

7 0
2 years ago
A helicopter starting on the ground is rising directly into the air at a rate of 25 ft/s. You are running on the ground starting
rusak2 [61]

Answer:

The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is \sqrt{725} ft/ sec

Explanation:

Given:

h(t) =  25 ft/sec

x(t) = 10 ft/ sec

h(5) = 25 ft/sec . 5 = 125 ft

x(5) = 10 ft/sec . 5 = 50 ft

Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem

D(t) = \sqrt{h^2 + x^2}

Lets find the derivative of distance with respect to time

\frac{dD}{dt} (t)  = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}

Substituting the values of h(t) and  x(t) and simplifying we get,

\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}

\frac{dh}{dt} = 25ft/sec

\frac{dx}{dt} = 10 ft/sec

\frac{Dd}{dt} (t) = \frac{1250t +200t}{2\sqrt{725}t}  = \frac{725}{\sqrt{725}}  = \sqrt{725} ft / sec

5 0
3 years ago
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