As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the in
1 answer:
Explanation:
It is given that,
Angle of incidence from air to another medium, i = 26°
The angle of reflection, r = 32°
We need to find the refractive index of the medium. The ratio of sine of angle of incidence to the sine of angle of reflection is called refractive index. It can be given by :
So, the index of refraction is 0.82. Hence, the correct option is C.
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The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.
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If the given turbine is assumed to be reversible;
(Initial pressure)=60 mpa = 60 bar
(Initial temperature)=600° C
(Exit pressure)=600 kpa=6 bar
The heat balance equation is;
The change in the entropy is;
The work done by the turbine is;
Hence,the work done by the turbine will be 708.2 kJ/kg.
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Answer:
n = 756.25 giga electrons
Explanation:
It is given that,
If the charge on the negative plate of the capacitor,
Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :
e is the charge on electron
or
n = 756.25 giga electrons
So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.
Answer:
Explanation:
The given data :-
- Diameter of rod AB ( d₁ ) = 200 mm.
- Diameter of rod BC ( d₂ ) = 150 mm.
- The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C
- The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
- Consider the required temperature increase to close the gap at C = T °C
- Consider the change in length of the rod = бL
Solution :-