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e-lub [12.9K]
2 years ago
8

___________________is the rate that an object moves in a certain direction.

Physics
1 answer:
AleksandrR [38]2 years ago
3 0

Answer:

Velocity

Explanation:

<u>Velocity</u> is the rate that an object moves in certain direction.

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In a comic book, superman carries a bus (with a bomb on board) up into the air, hovers for a second and then trows the bus over
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This breaks Newton's Second Law: For every action there is an equal and opposite reaction. The force exerted on the bus by superman should also be exerted on superman by the bus. Using the equation F=m*a, since superman's mass is so much less than the mass of the bus, he should experience a much higher acceleration than the bus does. So if the bus goes over the horizon, then superman should go MUCH further the other way. The caveat is that superman isn't able to change his density at will, which I believe is true in some storylines.
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4 years ago
An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the
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We can find the force by using the following formula;
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So, the force is 836 N.
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fenix001 [56]

Answer

The challenge when trying to protect the environment is expensive clean energy startup cost

Explanation

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4 0
3 years ago
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The cabinet is mounted on coasters and has a mass of 45 kg. The casters are locked to prevent the tires from rotating. The coeff
stira [4]

Answer:

the force P required for impending motion is 132.3 N

the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

Explanation:

Given that:

mass of the cabinet  m = 45 kg

coefficient of static friction μ =  0.30

A free flow body diagram illustrating what the question represents is attached in the file below;

The given condition from the question let us realize that ; the casters are locked to prevent the tires from rotating.

Thus; considering the forces along the vertical axis ; we have :

\sum f_y =0

The upward force and the downward force is :

N_A+N_B = mg

where;

\mathbf { N_A  \ and  \ N_B} are the normal contact force at center point A and B respectively .

N_A+N_B = 45*9.8

N_A+N_B = 441    ------- equation (1)

Considering the forces on the horizontal axis:

\sum f_x = 0

F_A +F_B  = P

where ;

\mathbf{ F_A \ and \ F_B } are the static friction at center point A and B respectively.

which can be written also as:

\mu_s N_A + \mu_s N_B  = P

\mu_s( N_A +  N_B)  = P

replacing our value from equation (1)

P = 0.30 ( 441)    

P = 132.3 N

Thus; the force P required for impending motion is 132.3 N

b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for  the cabinet is not to tip over is calculated by determining the limiting condition  of the unbalanced torque whose effect is canceled by the normal reaction at N_A and it is shifted to N_B:  

Then:

\sum M _B = 0

P*h = mg*0.24

h =\frac{45*9.8*0.24}{132.3}

h = 0.8 m

Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

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