Answer:
KE = 1/2mv^2
KE = 1/2(24)(3^2)
KE = 12(9)
KE = 108 J
Let me know if this helps!
Answer:
51 dioptre
Explanation:
u = Object distance = 2 cm
v = Image distance = 1 m
f = Focal length
Lens Equation
![\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{0.02}+\frac{1}{1}\\\Rightarrow \frac{1}{f}=\frac{1.02}{0.02}\\\Rightarrow \frac{1}{f}=51\\\Rightarrow f=\frac{1}{51}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bu%7D%2B%5Cfrac%7B1%7D%7Bv%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7B0.02%7D%2B%5Cfrac%7B1%7D%7B1%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1.02%7D%7B0.02%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7Bf%7D%3D51%5C%5C%5CRightarrow%20f%3D%5Cfrac%7B1%7D%7B51%7D)
Power of lens
![P=\frac{1}{f}\\\Rightarrow P=\frac{1}{\frac{1}{51}}\\\Rightarrow P=51\ D](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7Bf%7D%5C%5C%5CRightarrow%20P%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7B51%7D%7D%5C%5C%5CRightarrow%20P%3D51%5C%20D)
Power of the eye lens is 51 dioptre.
Answer:
The length of the bridge during the hottest part of summer is ![L_s = 1235.925 m](https://tex.z-dn.net/?f=L_s%20%20%3D%201235.925%20m)
Explanation:
From the question we are told that
The length of the steel bridge is ![L = 1234.567m](https://tex.z-dn.net/?f=L%20%3D%201234.567m)
The temperature for this length is ![T_1 = 233.15K](https://tex.z-dn.net/?f=T_1%20%3D%20233.15K)
The temperature at summer ![T_2 = + 140.0F = \frac{140 - 32}{180} *100 + 273= 333 K](https://tex.z-dn.net/?f=T_2%20%20%3D%20%2B%20140.0F%20%3D%20%5Cfrac%7B140%20-%2032%7D%7B180%7D%20%2A100%20%20%2B%20273%3D%20333%20K)
The coefficient of linear expansion is ![\alpha = 11.0123*10^{-6} K^{-1}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%2011.0123%2A10%5E%7B-6%7D%20K%5E%7B-1%7D)
Generally the change in length of the steel bridge is mathematically represented as
![\Delta L = \alpha L \Delta T](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%5Calpha%20L%20%5CDelta%20T)
Substituting value
![\Delta L = 11.0123*10^{-6} * 1234.567 (333-233.15)](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%2011.0123%2A10%5E%7B-6%7D%20%20%2A%201234.567%20%28333-233.15%29)
![\Delta L = 1.3575 \ m](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%201.3575%20%5C%20m)
The length of the bridge in summer is mathematically evaluated as
![L_s = L + \Delta L](https://tex.z-dn.net/?f=L_s%20%20%3D%20L%20%2B%20%5CDelta%20L)
Substituting values
![L_s = 1234.567 + 1.3575](https://tex.z-dn.net/?f=L_s%20%20%3D%201234.567%20%2B%201.3575)
![L_s = 1235.925 m](https://tex.z-dn.net/?f=L_s%20%20%3D%201235.925%20m)
According to newton's first law of motion a stationary or moving object will be in that state forever until an external force is exerted
Answer:
-1m
Explanation:
I'm assuming it means that you treat the distance travelled as a displacement vector (distance of a particular direction and magnitude)
If he turns 180 degrees, he is travelling in the exact opposite direction to his original direction of travel. Therefore if he was travelling 5m in one direction, then afer his turn he travels 6m in the exact opposite direction. Opposite directions can be interpreted as the negative of the original direction.
Resultant vectors are the sum of vectors.
The sum of vectors is equal to 5m + - 6m = -1m