You give the ball to the other team
Answer:
1.2 s
Explanation:
Given:
v₀ = 8.0 m/s
v = -4.0 m/s
a = -10 m/s²
Find: t
v = at + v₀
(-4.0 m/s) = (-10 m/s²) t + (8.0 m/s)
t = 1.2 s
Answer:
arge number of electrons free to move between the charged ions in the lattice.
Explanation:
The metallic bond occurs when an atom with few electrons is united in its last level, therefore the best way to decrease the total energy of the system is to lose all its electrons to remain with the configuration of a noble gas. The electrons that it loses cannot be acquired by other atoms since they all have few electrons, thus leaving a large number of electrons free to move between the charged ions in the lattice.
Some important characteristics emerge from this description of the metallic bond:
* It has many free electrons therefore its electrical conductivity is high
* As the charged ions are fixed, the material can be malleable, bent without breaking since the free electrons create the bond that keeps the system stable.
* As the electrons are free when heating a part of the material, these electrons acquire energy and rapidly propagate it to the other side, giving a high thermal conductivity
* As the temperature increases, the electrons acquire more kinetic energy, which is why there are more collisions between them and consequently the resistivity of the material increases.
Answer:
Light does not require any medium to travel because light is a transverse wave
hope it helps
Answer:
70 mph in only 168 feet is the largest
Explanation:
In which of those three situations is the magnitude of the car's acceleration the largest? In which of those three situations is the magnitude of the car's acceleration the largest? cornering at 0.85g reaching 60 mph in 5 seconds flat stopping from 70 mph in only 168 feet not enough information to determine
a)
convert miles/hour to ft/seconds
60mph
1 mile=5280ft
1hr=3600secs
= 60 * 5280 / 3600 ft/s
=> acceleration
acceleration is the rate of change in velocity
= [60 * 5280 / 3600] / 5 ft/s^2
= 264/15 ft/s^2
= 264/(15 * 32) g
= 0.55 g
magnitude of acceleration in case 2
= 0.85 g
magnitude of acceleration in case 3
recall from 
u=0
v^2/2s=a
velocity , a=acceleration
s=distance covered
= (70 * 5280 / 3600)^2 / (2 * 168 * 32) g
= 0.98 g
=> largest magnitude of acceleration = 0.98 g in case 3
and smallest magnitude of acceleration = 0.55 g in case 1.
