Answer:
no. of moles of PbI₂ = 14 moles
Explanation:
Data Given:
no. of moles of HI = 28 moles
no. of moles of Pbl₂ = ?
Reaction Given
Pb + 2HI -------→ Pbl₂ + H₂
Solution:
To solve this problem we have to look at the reaction
Reaction:
Pb + 2HI -------→ Pbl₂ + H₂
2 mol 1 mol
So if we look at the reaction 2 mole of hydrogen iodide (HI) gives 1 moles of Lead iodide (PbI₂), then how many moles of Lead iodide (PbI₂) will be produced by 28 moles of hydrogen iodide (HI)
For this apply unity formula
2 mole of HI ≅ 1 moles of PbI₂
28 mole of HI ≅ X moles of PbI₂
By Doing cross multiplication
moles of PbI₂ = 28 moles x 1 moles / 2 mole
moles of PbI₂ = 14 mole
28 mole of HI will produce 14 moles of PbI₂
Answer:
Temperature, heart rate and blood flow.
Explanation:
Data:
Q (Amount of heat) = 832 J
m (mass) = ?
c (Specific heat) = <span>0.90 J/(g × ° C)
T (final) = 97 ºC
To (initial) = 20 ºC
</span>ΔT = T - To → ΔT = 97 - 20 → ΔT = 77 ºC
Formula:
Q = m*c*ΔT
Solving:
Q = m*c*ΔT
832 = m*0.90*77
832 = 69.3m
69.3m = 832

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