Answer:
The rate of heat loss from the pipe by convection is 433113 Btu/h
Explanation:
Given that:
The length of the steam pipe = 300 ft
Temperature of the open space 
= 50 ° F
Outside diameter = 4 ㏑ = 4/12 ft = 0.333 ft
Avg, temperature of the surface of the pie 
= 280° F
Avg. convection of heat transfer h = 6 Btu/h·ft²·°F
We are to Determine the rate of heat loss from the pipe by convection
Let first calculate the area of the heat transfer;
A = πdh
A = πdL
A = π× 0.333 ft ×300 ft
A = 313.85 ft²
The rate of heat loss from the pipe by convection can now be calculated by using the formula:
Replacing our values from above ; we have:
Therefore, the rate of heat loss from the pipe by convection is 433113 Btu/h
Answer:
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Answer: 5.36×10-3kg/h
Where 10-3 is 10 exponential 3 or 10 raised to the power of -3.
Explanation:using the formula
M =JAt = -DAt×Dc/Dx
Where D is change in the respective variables. Insulting the values we get,
=5.1 × 10-8 × 0.13 × 3600 × 2.9 × 0.31 / 4×10-3.
=5.36×10-3kg/h
Answer with Explanation:
Part a)
The volume of water in the tank as a function of time is plotted in the below attached figure.
The vertical intercept of the graph is 46.
Part b)
The vertical intercept represents the volume of water that is initially present in the tank before draining begins.
Part c)
To find the time required to completely drain the tank we calculate the volume of the water in the tank to zero.
Part d)
The horizontal intercept represents the time it takes to empty the tank which as calculated above is 13.143 minutes.
Answer:
endurance length is 236.64 MPa
Explanation:
data given:
d = 37.5 mm
Sut = 760MPa
endurance limit is
Se = 0.5 Sut
= 0.5*760 = 380 MPa
surface factor is
Ka = a*Sut^b
where
Sut is ultimate strength
for AISI 1040 STEEL
a = 4.51, b = -0.265
Ka = 4.51*380^{-0.265}
Ka = 0.93
size factor is given as
Kb =1.29 d^{-0.17}
Kb = 0.669
Se = Sut *Ka*Kb
= 380*0.669*0.93
Se = 236.64 MPa
therefore endurance length is 236.64 MPa
