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alexgriva [62]
3 years ago
14

Help me, iv been having problems with ads going in my phones storage files, what can i do to stop this?

Engineering
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

so you can do this to avoid paying but you can just try to rest set your phone it sound crazy like you will loose all your contacts but you wont just re- set it. i mean u can try it other wise i dont know :)

Explanation:

hodyreva [135]3 years ago
7 0

Answer:

You can try pluging your phone into your computor and backing up your data onto itunes and factory resetting it then install your data back and see if that works.

Explanation:

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What material resources and intellectual resources were used in self driving cars?
fomenos

Answer: material resources: cameras, light detection and ranging systems, radar, sensors, advanced GPS, and millions of miles of training data, and more

I don't know about the intellectual resources sorry

5 0
3 years ago
Maintain a distance of at least
Virty [35]
The answer is c. 4 seconds
8 0
3 years ago
Read 2 more answers
How does java achieve portable
sergejj [24]

Answer:

Java is called portable because you can compile a java code which will spew out a byte-code, and then you run that code with Java Virtual Machine. Java Virtual Machine is like an interpreter, which reads the compiled byte-code and runs it. So first of all, you need to install the JVM on the system you want.

Explanation:

5 0
3 years ago
A particle moving on a straight line has acceleration a = 5-3t, and its velocity is 7 at time t = 2. If s(t) is the distance fro
Vikki [24]

Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7

<h3>How to solve for the value of s2 - s1</h3>

We have

= \frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt

= \int\limits^a_b {(5-3t)} \, dt

5t - \frac{3t^2}{2} +c

v2 = 5x2 -  3x2 + c

= 10-6+c

= 4+c

s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c

S2 - S1

=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)

= 6 + 6+c - 2+3+c

12+c-5+c = 0

7 = c

Read more on acceleration here: brainly.com/question/605631

5 0
2 years ago
Compute L, T, M, LC, and R and stations of the BC and EC for the circular curve with the given data of: I (delta) = 22°15′00" an
Mars2501 [29]

Answer:

L = 475.718

T = 240.89 ft

M = 23.0195

LC = 472.728

R = 1225 ft

Explanation:

See the attached file for the calculation.

8 0
3 years ago
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