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3 years ago

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The value of Rth is *

1 answer:

Vladimir79 [104]3 years ago

4 0

Johnjjjjjjhhhhhhhhjjjjjjjjjjj

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What is heuristic function? give examples <br>

zhuklara [117]

A heuristic function, is a function that calculates an approximate cost to a problem (or ranks alternatives). For example the problem might be finding the shortest driving distance to a point. A heuristic cost would be the straight line distance to the point

3 0

3 years ago

Niobium has a BCC crystal structure, an atomic radius of 0.143 nm and an atomic weight of 92.91 g/mol. Calculate the theoretical

Olin [163]

Answer:

The theoretical density for Niobium is $1.87 g/cm^3$ .

Explanation:

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density of the unit cell

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

We have :

Z = 2 (BCC)

M = 92.91 g/mol ( Niobium)

Atomic radius for niobium = r = 0.143 nm

Edge length of the unit cell = a

r = 0.866 a (BCC unit cell)

$a=\frac{0.143 nm}{0.866}=0.165 nm=0.165 \times 10^{-7} cm$

$1 nm = 10^{-7} cm$

On substituting all the given values , we will get the value of 'a'.

$\rho=\frac{2\times 92.91}{6.022\times 10^{23} mol^{-1}\times (0.165 \times 10^{-7} cm)^{3}}$

$\rho =1.87 g/cm^3$

The theoretical density for Niobium is $1.87 g/cm^3$ .

6 0

3 years ago

Read 2 more answers

Drag each item to show if it is an element or not an element.

miv72 [106K]

Everything is an element except for water, electron, and salt.

3 0

3 years ago

A block of mass 0.75 kg is suspended from a spring having a stiffness of 150 N/m. The block is displaced downwards from its equi

olganol [36]

Answer:

a)f=2.25 Hz

b)Time period T=.144 s

c)tex]V_{max}[/tex]=0.42 m/s

d)Phase angle Ф=87.3°

e) $a_{max}=6.0041 [tex]\frac{m}{s^2}$

Explanation:

a)

Natural frequency

$\omega _n=\sqrt {\dfrac{K}{m}}$

$\omega _n=\sqrt {\dfrac{150}{0.75}}$

$\omega _n$ =14.14 rad/s

w=2πf

⇒f=2.25 Hz

b) Time period

$=\dfrac{2π}{\omega _n}$

T= $\frac{1}{f}$

Time period T=.144 s

c)Displacement equation

$x=Acos\omega _nt+Bsin\omega _nt$

Boundary condition

t=o,x=0.03 m

t=0,v=.02m/s , V= $\frac{dx}{dt}$

Now by using these above conditions

A=0.03,B=0.0014

x=0.03 cos14.14 t+0.0014 sin14.14 t

⇒x=0.03003sin(14.14t+87.3)

$V_{max}=\omega_n X_{max}$

$V_{max}=14.14\times 0.03003$ =0.42 m/s

d)

Phase angle Ф=87.3°

e)

Maximum acceleration

$a_{max}=(\omega _n )^2X_{max}$

$a_{max}=(14.14)^20.03003$ =6.0041 $\frac{m}{s^2}$

3 0

4 years ago

Read 2 more answers

What character string does the binary ASCII code 1010100 1101000 1101001 1110011 0100000 1101001 1110011 0100000 1000101 1000001

Radda [10]

Answer: This is EASY!

Explanation:

To make it easy, you would convert those binary numbers and to denary. And this gives:

84 104 105 115 32 105 115 32 69 65 83 89 33

Then, the denary numbers generated can be converted to ASCII code using this ASCII Table in the attachment below. And the result is: This is EASY!

4 0

4 years ago