Answer:
strains for the respective cases are
0.287
0.318
0.127
and for the entire process 0.733
Explanation:
The formula for the true strain is given as:

Where
True strain
l= length of the member after deformation
original length of the member
<u>Now for the first case we have</u>
l= 1.6m

thus,


<u>similarly for the second case we have</u>
l= 2.2m
(as the length is changing from 1.6m in this case)
thus,


<u>Now for the third case</u>
l= 2.5m

thus,


<u>Now the true strain for the entire process</u>
l=2.5m

thus,

Answer:
The answer which is a calculation can be found as an attached document
Explanation:
Answer:
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Explanation:
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Answer:
P = 0.490 kip
Explanation:
given data
allowable bearing stress = 2 ksi
allowable tensile stress = 18 ksi
diameter = 0.31 in
outer diameter = 0.75 in
inner diameter (hole) = 0.50 in
solution
we find here cross section area of shank that is express as
Area =
..................1
area =
area = 0.0754 in²
and
now we get here allowable load in bolt will be
...................2
P =
P = 18 × 10³ × 0.0754
P = 1357.2 = 1.357 kip
and
now find here area of washer is
Area =
.......................3
put here value
Area =
area = 0.2454 in²
so now we get here allowable load of washer will be
.....................4
P = 2 × 10³ × 0.245
P = 490 = 0.490 kip