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3 years ago

Which index of refraction represents the most optically dense material?

2 answers:

6 0

The relation between the refractive index and the optical density of the material is a direct relation.
This means that the more the refractive index is, the more optically dense the material is.

Based on the above, when checking the given choices, the refractive index that represents the most optically dense material would be the largest refractive index which is:
<span>d. 2.65</span>

Tju [1.3M]3 years ago

6 0

Answer:

Explanation:It does ask for the most optically dense NOT the least.

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What is undefined <br> I need help I don't understand this question

Wittaler [7]

(4/9-9) and (4/0) are undefined as you can not divide by the value of 0.

6 0

3 years ago

Read 2 more answers

The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 a

Tju [1.3M]

Coefficient of static friction = 0.5
Coefficient of Kinetic friction = 0.3
Angular velocity = 500 RPMs

<h3>The Radius of the System</h3>

Let R be the radius of cylinder

$m_a + m_b = 4 + 3 = 7kg$

The angular velocity is 500 RPMs

$\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R$

The normal force

$f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm$

Since the radius is very little for two block to execute circular motion so system will slide down.

Learn more on coefficient of static friction here;

brainly.com/question/11841776

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brainly.com/question/26400616

8 0

2 years ago

The heat required to melt a piece of copper is (82 x 10 ^5 J). The heat of fusion of copper is (2.05×10 ^5 J/ kg). What is the m

Musya8 [376]

Answer:

Explanation:

Givens

Heat of Fusion = 2.05 * 10^5 J / kg watch the units.

Heat to actually melt the copper = 82 10^5 J

Formula

Mass of copper = Heat / Heat of Fusion

Solution

Mass of copper = 82*10^5 J / (2.05 * 10^5 J / kg)

Mass of copper = 40 kg

Notice that the kg is in the denominator of the second fraction. The rules of fractions would tell you the 1/1 / / 1 /kg . You take the right fraction and turn it upside down and multiply. 1 / 1 * kg/1 = 1* kg / 1*1 which is just kg.

Answer 40 kg of copper

4 0

2 years ago

A charged capacitor is connected to an ideal inductor. At time t = 0, the charge on the capacitor is equal to 6.00 μC. At time t

Len [333]

Answer:

$4.71\times 10^{-3}A$