3 years ago

Find the perimeter of a rectangle with length 7x - 2 and width 5x^2 + 1.

Mathematics

1 answer:

stealth61 [152]3 years ago

4 0

Answer:

10x^2 + 14x - 2

Step-by-step explanation:

So for the perimeter, you have to solve 2(7x-2) + 2(5x^2+1)

So distribute the 2s on both s we get 14x - 4 + 10x^2 + 2

This in standard form is 10x^2 + 14x - 2

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