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nataly862011 [7]
3 years ago
8

Choose all items which are true.

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

y98

Step-by-step explanation:

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9k2-12k+4

(k2-6k)+(-6k+4) factor out the 3k from 9k2 0 6k: 3k(k-2) factor out -2 from -6k +4n: -2 (3k-2) factor out common term (3k-2) = (3k-2 ) (3k-2) that equals (3k-2)2
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Step-by-step explanation:

5 0
3 years ago
As his empire spread throughout the ancient world, Alexander founded roughly how many cities?
Studentka2010 [4]
About 70 Cities in Total.

For his more noteworthy grandness, Alexander established exactly 70 urban areas in the grounds he vanquished and requested them named after himself. Most celebrated, obviously, is Alexandria in Egypt. In India, when his dearest horse kicked the bucket, he requested a city to be constructed named Bucephala.
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Help me plzzz!! I need to get this right.
NARA [144]

The formula for circumference is

C=(pi)d

11304=(pi)d

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3 0
3 years ago
Read 2 more answers
If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun
AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

               Nonsmokers      Light Smoker     Heavy smoker      Total

Men                        303                     35                           37        375

Women                   413                     31                            45        489

Total                        716                     66                           82        864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

82C2=\frac{82!}{2!(82-2)!}=3321

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

864C2=\frac{864!}{2!(864-2)!}=372816

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908

4 0
3 years ago
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