A 55.0 g piece of iron at 505 ° C is put into 735 grams of water at 15.0 ° C. What is the final temperature of the water and the
1 answer:
You might be interested in
Answer:
The answer to your question is d. 0.5 M
Explanation:
Data
[A] = 1M
K = 0.5
Concentration of B and C at equilibrium = x
Concentration of A at equilibrium = 1 - x
Equation of equilibrium
k =
Substitution
Simplification
0.5 =
Solve for x
0.5(1 - x) = x²
0.5 - 0.5x = x²
x² + 0.5x - 0.5 = 0
Find the roots x₁ = 0.5 x₂ = -1
There are no negative concentrations so the concentration of A at equilibrium is
[A] = 1 - 0.5
= 0.5 M
Answer:
You need to dissolve 144 gr of glucose in 0.8 liters of water to have a 1 M solution.
Explanation:
Molarity is the amount of moles per liter of solution --> moles/liters. We are trying to get a 1 molar solution and we also know the liters (0,8L) so
after canceling liters of water you get 0,8 moles of glucose.