All categories

3 years ago

What is the ideal gas constant?

Chemistry

1 answer:

AURORKA [14]3 years ago

4 0

Answer:

Ideal gas constant is a universal constant used for all gases

Explanation:

In Ideal Gases Law, the Ideal gas constant is called R.

It can also be used in Van der Waals equation or, in thermodynamic equations.

R = 0.082 l.atm/mol.K

It is related to the Boltzmann constant, a number that links energy units with temperature units.

You might be interested in

Conduction and Convection involve the movement of particles. Radiation does not True or False

Rom4ik [11]

Answer:

False

Explanation:

Because it is false heat will always transfer so it require matter

6 0

3 years ago

Read 2 more answers

How many valence electrons does B (boron) have? A. 13 B. 5 C. 10 D. 3

pshichka [43]

Answer:

Boron has 3 valence electrons

8 0

2 years ago

How to know what elements are least likely to form ions?

viktelen [127]

Aluminum mixed iron .Al + fe = AlFe3

4 0

3 years ago

Read 2 more answers

Which chemical formula represents both an element and a molecule?

victus00 [196]

Answer:

Explanation:

element - a basic substance that can't be simplified (hydrogen, oxygen, gold, etc...) molecule - two or more atoms that are chemically joined together (H2, O2, H2O, C6H12O6, etc...) compound - a substance that contains more than one element (H2O, C6H12O6, etc...)

5 0

1 year ago

How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac

Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

• using the molar mass of Ca(OH)2 (74g/mol).

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

• using the molar mass of HNO3 (63.02g/mol).

$4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3$

So, 7.32g of HNO3 are required.

4 0

1 year ago