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r-ruslan [8.4K]
3 years ago
15

PLEASE HELP!!

Chemistry
1 answer:
sp2606 [1]3 years ago
6 0
Inbox me for the answer

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The p K a pKa of acetic acid is 4.76 . 4.76. The p K a pKa of trichloroacetic acid is 0.7 . 0.7. Calculate the equilibrium disso
Andrei [34K]

Answer:

Acetic acid Ka = 1.74 × 10⁻⁵

Trichloroacetic acid Ka = 2 × 10⁻¹

Explanation:

Let's consider the acid dissociation of acetic acid.

CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq)

The pKa of acetic acid is 4.76. The acid dissociation constant (Ka) is:

pKa = -log Ka

- pKa = log Ka

Ka = anti log (-pKa)

Ka = anti log (-4.76)

Ka = 1.74 × 10⁻⁵

Let's consider the acid dissociation of trichloroacetic acid.

CCl₃COOH(aq) ⇄ CCl₃COO⁻(aq) + H⁺(aq)

The pKa of trichloroacetic acid is 0.7. The acid dissociation constant (Ka) is:

pKa = -log Ka

- pKa = log Ka

Ka = anti log (-pKa)

Ka = anti log (-0.7)

Ka = 2 × 10⁻¹

3 0
3 years ago
this is so CONFUSING WTH anyone kind to help with those two questions just answer how much you know, I’ll still brainlist it’s u
Ganezh [65]

Answer:

4. mutualism - both benefit

5. Commensalism- one benefits while the other is not affected

"Mutualism is a symbiotic relationship in which both species benefit. Commensalism is a symbiotic relationship in which one species benefited while the other species is not affected."

3 0
2 years ago
I cant explain this really
Free_Kalibri [48]

Answer:

B.

Explanation:

8 0
3 years ago
135-g sample of a metal requires 2.50 kJ to change its temperature from 19.5 C to 100.0 C what is the specific heat of this meta
Harman [31]
The temperature increase is from 19.5 to 100 degrees centigrade or 80.5 degrees centigrade. The calorie increase is 2.50 x 1000 x 0.238902957619 or a total of 597.25 calories. 597.25/80.5 = 7.419 calories per degree centigrade. 7.419/135 grams = 0.0549 calories/gram/degree centigrade. The conversion from kilo joules involves multiplying the calories per joule x 1000 to get the number of calories in one kilo joule and then by the 2.5. 
3 0
3 years ago
a student determined that it requires 106220 j of energy to vaporize 47g of water. is the student is right​
shusha [124]
<h2>Answer:</h2>

He is right that the energy of vaporization of 47 g of water s 106222 j.

<h3>Explanation:</h3>

Enthalpy of vaporization or heat of vaporization is the amount of energy which is used to transform one mole of liquid into gas.

In case of water it is 40.65 KJ/mol. And 18 g of water is equal to one mole.

It means for vaporizing 18 g, 40.65 kJ energy is needed.

So for energy 47 g of water = 47/18 * 40.65 = 106.1 KJ

Hence the student is right about the energy of vaporization of 47 g of water.

7 0
3 years ago
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