1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
abruzzese [7]
3 years ago
14

Help me please!! :D​

Chemistry
1 answer:
dem82 [27]3 years ago
4 0

Answer: Solar eclipse

Explanation:

You might be interested in
A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35?C. If there are 9750 moles of oxygen in the tan
Paul [167]

Answer:

2192.64 PSI.

Explanation:

  • From the general law of ideal gases:

<em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the container in L (V = 1650 L).

n is the no. of moles of the gas in mol (n = 9750 mol).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gas in (T = 35°C + 273 = 308 K).

∴ P = nRT/V = (9750 mol)(0.082 L.atm/mol.K)(308 K)/(1650 L) = 149.2 atm.

  • <u><em>To convert from atm to PSI:</em></u>

1 atm = 14.696 PSI.

<em>∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.</em>

4 0
3 years ago
Use the graph to answer these questions. The total energy of the reactants is –3,811.92 kJ. –1,273.02 kJ. –2,538.90 kJ.
TEA [102]

Answer:

the first one

Explanation:

8 0
3 years ago
Read 2 more answers
Covalent bonding involves the sharing of electrons to create a full valence shell, and
Leno4ka [110]
True. Covalent bonds involve sharing electrons to create a full valence shell.
8 0
2 years ago
Read 2 more answers
General Chemistry fourth edition by McQuarrie, Rock, and Gallogly. University Science Books presented by Macmillan Learning.
Helen [10]

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

  • Q: heat absorbed
  • C: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)
  • ΔT: temperature change (2.29 °C)

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

3 0
3 years ago
What is the name for this molecule? 3-heptyne 3-heptene 3-hexyne 3-hexene
sweet-ann [11.9K]

The iupac name of the compound will be hex-3-yne or 3-hexyne. By marking number of carbon in the given compound, it was found that triple bond comes at third position and there are total 6 carbon in the compound. So it will have Hex as a prefix and as it contains triple bond so it will have yne as a suffix and as the triple bond is at third position, so it will be hex-3-yne or 3-hexyne.

3 0
3 years ago
Read 2 more answers
Other questions:
  • What factors alter the equilibrium position in chemical reactions?
    11·1 answer
  • Why did improvements in agriculture lead to the growth of cities?
    13·1 answer
  • When balancing a redox reaction, you are balancing
    8·1 answer
  • Find ΔHrxn for the following reaction: <br><br> 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)
    11·1 answer
  • Sometimes the color of an animal closely resembles the color of its environment. Which of the following is the most likely reaso
    14·2 answers
  • 5. Do you think oppositional or symbiotic relationships are more beneficial to an ecosystem? Justify
    14·1 answer
  • Each 5-ml teaspoon of Extra Strength Maalox Plus contains 450 mg of magnesium hydroxide and 500 mg of aluminum hydroxide. How ma
    5·1 answer
  • Hybridization of Al in AlF3
    9·1 answer
  • How many moles of ethanol C2H6O, are in a 10.0g sample​
    13·1 answer
  • Rank the following molecules (1st, 2nd, 3rd, 4th) in the order that they melt.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!