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snow_lady [41]
3 years ago
8

Which action might lead scientists to develop new explanations about the universe?

Physics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

Designing experiments to replicate the conditions in which life may have first evolved on Earth

Explanation:

In 1953, Stanley L. Miller and Harold C. Urey conducted an experiment to prove that life started from inanimate objects. The research was conducted by utilizing proposed chemical substances, mixed together through a scientific design process. The outcome of the research is the predicted atmospheric conditions before the pre-living form started on earth.

Therefore, in this case, the action that might lead scientists to develop new explanations about the universe is "Designing experiments to replicate the conditions in which life may have first evolved on Earth."

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Anyone please helps me with this question... I'm stuck..
Zolol [24]
Highest fluid potential energy: answer A
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7 0
3 years ago
An electromagnetic wave is traveling straight down toward the center of the Earth. At a certain moment in time the electric fiel
Anika [276]

Answer:

North

Explanation:

In an electromagnetic wave, the direction of the wave, the direction of the electric field and the direction of the magnetic field are all perpendicular to each other.

Therefore, we can  find the direction of the magnetic field by using the right hand rule. We have:

- Index finger: direction of motion of the wave --> toward the center of Earth

- middle finger: direction of the electric field --> west

- thumb: direction of the magnetic field --> north

So, the magnetic field points north.

3 0
3 years ago
A particle's position is given by z(t) = −(6.50 m/s2)t2k for t ≥ 0. (Express your answer in vector form.) a. Find the particle's
blondinia [14]

Answer:

a) z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

b) v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

Explanation:

The particle position is given by:

z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

z'(t) =v(t) = -13t

Now we can replace the velocity for t=1.75 s

v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}

For t = 3.0 s we have:

v(3.0s) = -13*3.0 =-39 \frac{m}{s}

Part b

For this case we can find the average velocity with the following formula:

v_{avg}= \frac{z_f - z_i}{t_f -t_i}

And we can find the positions for the two times required like this:

z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m

z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m

And now we can replace and we got:

V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}

8 0
3 years ago
Hi, does anyone know the answer for question 2 or 3? Thank you
Anna007 [38]

Answer:

n

Explanation:

4 0
3 years ago
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