Hi, does anyone know the answer for question 2 or 3? Thank you

11 Design Imagine that a scientistdiscovered a way to make africtionless surface. What wouldbe some useful applications forthis

m_a_m_a [10]

Answer:

You could move something across the Earth with a little push. It would make fuel really efficient on those pathways. You could make a floor that is impossible to walk on. Everybody would just fall without traction.

Explanation:

3 0

3 years ago

If you push on the wall with a force of 400 N, what is the magnitude of the force at the wall exerts on you?

Inessa05 [86]

Answer:

400 N

Explanation:

Due to action-Reaction, the wall pushes back on the person with a force of equal magnitude and in opposite direction to the force exerted by the person.

So the magnitude must be also 400 N.

7 0

3 years ago

What mass of a material with density ρ is required to make a hollow spherical shell having inner radius r1 and outer radius r2?

krok68 [10]

Answer: $m=\frac {\rho}{\frac{4}{3} \pi( (r_2)^{3} - (r_1)^{3}) }$

It is given that:

Density of material =ρ

radius of inner spherical shell = $r_1$

radius of outer spherical shell= $r_2$

we know that the volume of sphere is $\frac{4}{3}\pi r^{3}$

Volume of the given spherical shell = $\frac{4}{3}\pi( (r_2)^{3}-(r_1)^{3})$

Then mass of the spherical shell can be calculate as:

Mass, m=density/ volume

$m=\frac {\rho}{\frac{4}{3} \pi ((r_2)^{3} - (r_1)^{3}) }$

6 0

3 years ago

Many of today’s mathematicians use computers to test cases that ___

vekshin1

Many of today’s mathematicians use computers to test cases that are either too time-consuming or involve too many variables to test manually, allowing the exploration of theoretical issues that were impossible to test a generation ago.

Answer: Option A

<u>Explanation:</u>

One of the most useful inventions in scientific world are the computers. We can use different programming language and create programs in them. These programs help other to solve difficult problems. Most of the theoretical problems in science can be solved by using these programming features in computer within a specific time limit.

Otherwise, earlier mathematician used to take months to solve a complex mathematical problem manually, but now with the inclusion of computers, the mathematician can solve the problems containing more number of variables or other theoretical issues.

7 0

3 years ago

Take the following measured gauge (or gage) pressures and convert them to absolute pressures in both kPa and psi units for an am

mamaluj [8]

Answer:

Explanation:

Given

ambient Pressure =98.10 kPa

(a)gauge pressure 152 kPa

we know

Absolute pressure=gauge pressure+Vacuum Pressure

$P_{abs}$ =152+98.10=250.1 kPa or 36.27 psi

(b) $P_{gauge}$ =67.5 Torr or 8.99 kpa

as 1 Torr is 0.133 kPa

$P_{abs}$ =8.99+98.10=107.09 kPa or 15.53 psi

(c) $P_{vaccum}$ =0.1 bar or 10 kPa

Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi

as 1 kPa is equal to 0.145 psi

(d) $P_{vaccum}$ =0.84 atm or 85.113 kPa

as 1 atm is equal to 101.325 kPa

$P_{abs}$ =98.10-85.11=12.99 kPa or 1.88 psi

6 0

3 years ago