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natali 33 [55]
3 years ago
8

If f(x)=3x+2, find the following value: f(4)=?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer:

f(4)=14

Step-by-step explanation:

f(x)=3x+2

f(4)=3x+2

f(4)=3*4+2

f(4)=12+2

f(4)=14

Hope this helps!

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A basket contains four apples and six peaches. You randomly select one piece of fruit and eat it. Then you randomly select anoth
Sveta_85 [38]

Answer:

Answer as a fraction: 4/15

Answer as a decimal: 0.267

The decimal version is approximate rounded to three decimal places.

Step-by-step explanation:

6 apples, 4 peaches

6+4 = 10 pieces of fruit total

The probability of picking an apple is 6/10 = 3/5

After you pick and eat the apple, there are 10-1 = 9 pieces of fruit left. Also, the probability of picking a peach is 4/9, as there are 4 peaches out of 9 fruit left over.

Multiply out 3/5 and 4/9 to get (3/5)*(4/9) = (3*4)/(5*9) = 12/45 = 4/15

Using a calculator, 4/15 = 0.267 approximately.

6 0
2 years ago
Hannah wants to buy a $540 camera. She can save $40 each week from her paycheck. However, before Hannah can buy the camera, she
Natasha_Volkova [10]

Answer:

w = 12

Step-by-step explanation:

Create formula:

540 = 40w - 60 where 540 is the cost of the camera, 40 is the amount saved, w is the number of weeks, 60 is the amount owed

Solve for w

540 = 40w - 60: subtract 60

480 = 40w: divide by 40

w = 12

7 0
3 years ago
4/5x=56 Please help, and explain how you got it
Scrat [10]
To solve this, we must isolate x (have it by itself).

4/5x = 56

Multiply each side by 5x.

4/5x(5x) = 56(5x)

Divide each side by 280.

4/280 = 280x/280

Solve.

0.014 = x

0.014 can also be written as 1/70

:)

5 0
3 years ago
HELP!
Marina86 [1]

Answer:

117.3 ft³

Step-by-step explanation:

The equation for the volume of a cone of radius r and height h is

V = (1/3) π r² h.

Here, V = (1/3) π (4 ft)² (7 ft) = 117.3 ft³

3 0
3 years ago
Hi need help for this maths question
Sauron [17]

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}

c) The mean is given by the integral,

\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy

Integrate by parts, with

u = y \implies du = dy

dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}

Then

\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)

\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy

\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}

8 0
2 years ago
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