3-6 seconds time interval is the object slowing down.
The correct option is C.
<h3>What is a time interval?</h3>
The time interval is the span of time among two specified times. To put it another way, it is the amount of time that has passed between the event's start and finish.
<h3>What are different time intervals?</h3>
The time interval is the length of time that the aim uses to gather data and determine values. The critical overview can be one or more seconds, minutes, hours, days, weeks, or months. The period must be greater than zero and positive. When providing minutes, the amount of minutes must divide evenly by 60.
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The complete question is -
During which time interval is the object slowing down ?
a- 8-10 seconds
b- 6-8 seconds
c- 3-6 seconds
d- 0-3 seconds
R = 18 ohms
Explanation:
Given:
V = 36 volts
I = 2.0 A
R = ?
Use Ohm's law to solve for the resistance:
V = IR
or
R = V/I
= (36 volts)/(2.0 A)
= 18 ohms
Answer: <span>Protons do not move out of the nucleus of atoms although they repel each other.
Reasoning:
Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.
That repulsion force tends to destabilize the atom. The only reason why the atom does not explode is because there is a there exists a force of attraction that exceeds the repulsion of the like charged protons. That is the strong nuclear force. Therefore, the strong nuclear forces are stronger than the electromagnetic force that tends to get the protons apart.
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Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.
Answer:
Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).
Explanation:
Given:
Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s
first to find Electric Force
F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)
We also have F=ma
⇒ a = F/m = - 8 × 10⁻⁵ N / 10 × 10⁻⁵ kg = -8 m/s² ( -ve sign shows that the particle is accelerated opposite to positive x- direction)
Now according the first equation of Motion.
Vf = Vi + at
Vf = 20 m/s + -8 m/s² × 5 s
Vf= -20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction)
