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Lostsunrise [7]
2 years ago
11

A wire 40cm long and of diameter 0.60mm has a resistance of 1.5 ohm what is the resistivity of the material of which it is made

taking pie to be 3.14​
Physics
1 answer:
zavuch27 [327]2 years ago
3 0

Answer:

The resistivity of the wire is 1.05\times 10^{-6}\ \Omega-m

Explanation:

We have,

Length of a wire is 40 cm or 0.4 m

Diameter of a wire is 0.60 mm

Radius is 0.3 mm or 0.0003 m

Resistance of a wire is 1.5 ohm

Now we need to find the resistivity of the material of which it is made. The resistance of a wire in terms of its resistance, length and area is given by :

R=\rho \dfrac{l}{A}

\rho = resistivity

\rho=R \dfrac{\pi r^2}{l}\\\\\rho=1.5\times  \dfrac{3.14\times (0.0003 )^2}{0.4}\\\\\rho=1.05\times 10^{-6}\ \Omega-m

So, the resistivity of the wire is 1.05\times 10^{-6}\ \Omega-m.

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a) 4 forces

b) 186 N

c) 246 N

Explanation:

a)

Let's count the forces acting on the bicylist:

1) Weight (W=mg): this is the gravitational force exerted on the bicyclist by the Earth, which pulls the bicyclist towards the Earth's centre; so, this force acts downward (m = mass of the bicyclist, g = acceleration due to gravity)

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3) Applied force (F_A): this is the force exerted by the bicylicist to push the bike forward. Its direction is forward

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b)

Here we can find the net force on the bicyclist by using Newton's second law of motion, which states that the net force acting on a body is equal to the product between the mass of the body and its acceleration:

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F_{net} is the net force

m is the mass of the body

a is its acceleration

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m = 60 kg is the mass of the bicyclist

a=3.1 m/s^2 is its acceleration

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c)

We can write the net force acting on the bicyclist in the horizontal direction as the resultant of the two forces acting along this direction, so:

F_{net}=F_a-R

where:

F_{net} is the net force

F_a is the applied force (forward)

R is the air drag (backward)

In this problem we have:

F_{net}=186 N is the net force (found in part b)

R=60 N is the magnitude of the air drag

Solving for F_a, we find the force produced by the bicyclist while pedaling:

F_a=F_{net}+R=186+60=246 N

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