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Svetach [21]
3 years ago
12

Why do real gases not behave exactly like ideal gases?

Chemistry
1 answer:
mihalych1998 [28]3 years ago
8 0

Answer:

Real gas particles have significant volume

Real gas particles have more complex interactions than ideal gas particles.

Explanation:

An ideal gas is an imaginary concept and a gas behaves almost ideally at certain pressure and temperature conditions.

The gas in real deviates from the ideal behavior as some of the assumptions made for ideal gases are not true in case of real gases.

Real gas particles have significant volume as compared to vessel unlike ideal gases.

There are interactions present in between real gas molecules at high pressure conditions.

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the element weighed 3.555 grams when it was burned in oxygen an oxide compound was produced. the product mass was 4.666 grams. W
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Idk really but i hope you figure out the answer im not on that yet.
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3 years ago
Dehydration of 2-methyl-2-pentanol forms one major and one minor organic product. Draw the structures of the two organic product
Korvikt [17]

Answer:

The major product is 2-methyl-2-pentene [ CH₃-CH₂-CH=C(CH₃)₂ ] and a minor product 2-methyl-1-pentene [ CH₃-CH₂-CH₂-C(CH₃)=CH₂ ].

Explanation:

Dehydration reaction is a reaction in which a molecule loses a water molecule in the presence of a dehydrating agent like sulfuric acid (H₂SO₄).

<u>Dehydration reaction of 2-methyl-2-pentanol</u> gives a major product 2-methyl-2-pentene and a minor product 2-methyl-1-pentene.

CH₃-CH₂-CH₂-C(CH₃)₂-OH (2-methyl-2-pentanol)→ CH₃-CH₂-CH=C(CH₃)₂ (2-methyl-2-pentene, major) + CH₃-CH₂-CH₂-C(CH₃)=CH₂ (2-methyl-1-pentene, minor)

<u>Since more substituted alkene is more stable than the less substituted alkene. So, the trisubstituted alkene, 2-methyl-2-pentene is more stable than the disubstituted alkene, 2-methyl-1-pentene.</u>

<u>Therefore, the trisubstituted alkene, 2-methyl-2-pentene is the major product and the disubstituted alkene, 2-methyl-1-pentene is the minor product.</u>

7 0
3 years ago
Which is always going to be the highest ionization energy?
Law Incorporation [45]

Answer: I think it's B.

Explanation:

4 0
2 years ago
What is thermal equilibrium? equal temperature equal heat equal thermal energy equal conductivity
Margarita [4]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

I believe the answer would be A. equal temperature

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Stay Brainly! ヅ    

- Ally ✧    

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6 0
3 years ago
Read 2 more answers
Can somebody help me, please!
zavuch27 [327]

Answer:

Rubidium-85=61.2

Rubidium-87=24.36

Atomic Mass=85.56 amu

Explanation:

To find the atomic mass, we must multiply the masses of the isotope by the percent abundance, then add.

<u>Rubidium-85 </u>

This isotope has an abundance of 72%.

Convert 72% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 72/100= 0.72      or        72.0 --> 7.2 ---> 0.72

Multiply the mass of the isotope, which is 85, by the abundance as a decimal.

  • mass * decimal abundance= 85* 0.72= 61.2

Rubidium-85=61.2

<u>Rubidium-87</u>

This isotope has an abundance of 28%.

Convert 28% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 28/100= 0.28       or        28.0 --> 2.8 ---> 0.28

Multiply the mass of the isotope, which is 87, by the abundance as a decimal.

  • mass * decimal abundance= 87* 0.28= 24.36

Rubidium-87=24.36

<u>Atomic Mass of Rubidium:</u>

Add the two numbers together.

  • Rb-85 (61.2) and Rb-87 (24.36)
  • 61.2+24.36=85.56 amu
4 0
3 years ago
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