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Svetach [21]
3 years ago
12

Why do real gases not behave exactly like ideal gases?

Chemistry
1 answer:
mihalych1998 [28]3 years ago
8 0

Answer:

Real gas particles have significant volume

Real gas particles have more complex interactions than ideal gas particles.

Explanation:

An ideal gas is an imaginary concept and a gas behaves almost ideally at certain pressure and temperature conditions.

The gas in real deviates from the ideal behavior as some of the assumptions made for ideal gases are not true in case of real gases.

Real gas particles have significant volume as compared to vessel unlike ideal gases.

There are interactions present in between real gas molecules at high pressure conditions.

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How many moles in 4.65 g of Helium?
Maru [420]

Answer:

4.65 g x 1 mol/4.0026 g/mol = 1.162 mol helium

Explanation:

7 0
3 years ago
A sample of helium gas initially at 37.0°C, 785 torr and 2.00 L was heated to 58.0°C while the volume expanded to 3.24 L. What i
spayn [35]

Answer:

0.681 atm

Explanation:

To solve this problem, we make use of the General gas equation.

Given:

P1 = 785 torr

V1 = 2L

T1 = 37= 37 + 273.15 = 310.15K

P2 = ?

V2 = 3.24L

T2 = 58 = 58+273.15 = 331.15K

P1V1/T1 = P2V2/T2

Now, making P2 the subject of the formula,

P2 = P1V1T2/T1V2

P2 = [785 * 2 * 331.15]/[310.15 * 3.24]

P2 = 515.715 Torr

We convert this to atm: 1 torr = 0.00132 atm

515.715 Torr = 515.715 * 0.00132 = 0.681 atm

8 0
3 years ago
What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?
lawyer [7]
  • Density=2.35g/mL
  • Mass=33.67g

\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}

\\ \star\sf\longmapsto Volume=14.32mL

6 0
3 years ago
You can decide if a paint booth filter is hazardous waste by answering which of the following questions:
BaLLatris [955]

Answer: (D) Are there solvents mixed in (or is it water based)?

3 0
3 years ago
A 800N mountain climber scales a 160m cliff. How much work is done by the mountain climber?
Fittoniya [83]

Answer:

Work done, W = 128 kJ

Explanation:

Given that,

Weight of a mountain climber, F = 800 N

It climbs to a cliff that is 160 m high.

We need to find the work done by the mountain climber. The work done by an object is given by the formula as follows :

W = Fd

Put the values of F and d.

W = 800 N × 160 m

W = 128000 J

or

W = 128 kJ

So, 128 kJ of work is done by the mountain climber.

3 0
2 years ago
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