Area=1/2 times base times height
note:bh=base times height
a=1/2bh
b=width
h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0
so
w-9=0
w+7=0
solve each
w-9=0
add 9 to both sdies
w=9
w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded
width=9
subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14
legnth=14 in
width/base=9 in
Answer:
Step-by-step explanation:
For example, the base-8 numeral 23-8 contains two digits, "2" and "3", and with a base number (subscripted) "8". When converted to base-10, the 23-8 is equivalent to 19-10, i.e. 23-8 = 19-10.
Answer:2,262in.^3
Step-by-step explanation:
Answer:
b ) a^7/b^6 is the correct answer
4(.5*7*9)+(7*7)=175 sq cm
