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Vika [28.1K]
3 years ago
12

Consider the following generic chemical equation: 2W + 3X → 3Y + Z When 5 units of W and 6 units of X are allowed to react, the

limiting reactant would be:a) W.b) X.c) Y.d) Z.
Chemistry
1 answer:
aliina [53]3 years ago
8 0

Answer:

The answer to your question is letter b) X

Explanation:

Data

W = 5 units

X = 6 units

Chemical reaction

                              2W  + 3X   ⇒  3Y  +  Z

To determine which reactant is the limiting reactant, we must use proportions:

-Theoretical proportion   W / X  = 2 / 3 = 0.67

- Experimental proportion W / X = 5 / 6 = 0.83

As the experimental proportion is higher than the theoretical proportion, we conclude that the amount of W is higher in the experiment so the limiting reactant is X.

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Helppp please pleaseeee
boyakko [2]

Answer:

D

Explanation:

The answer will be D because as we can deduct from the hypothesis, he will try to control the amount of food he gives the rats in order to see if in fact the fue of the mouse will be shinier

3 0
4 years ago
A gas mixture being used to simulate the atmosphere of another planet at 23°c consists of 337 mg of methane, 148 mg of argon, an
Karolina [17]

The total pressure of the mixture is 65.5 kPa.

According to Dalton's Law of Partial Pressure,

The partial pressure of gas = Mole fraction of gas × Total pressure

Total Pressure = Sum of all the gases partial pressures

The number of moles of methane is,

Moles \:  of \: methane  \: (16 g/mol) =  337 \: mg  \times  \frac{1 g}{1000 mg} \times  \frac{ 1 mol}{16 g }

= 0.021 mols

The moles of methane are 0.021 mols.

The number of moles of the argon,

Moles \:  of \: argon (40 g/mol) = 148 \:  mg  \times  \frac{  1 g}{1000 mg } \times  \frac{  1 mol}{40 g}

= 0.003 mols

The number of moles of argon is 0.003 mols.

The number of moles of nitrogen is,

Moles  \: of \: nitrogen (28 g/mol) = 296 \:  mg  \times  \frac{ 1 g}{1000 mg}  \times  \frac{  1 mol/}{28 g}

= 0.010 mols

The number of moles of nitrogen is 0.010 mols.

The total number of moles is,

= 0.021 + 0.003 + 0.010

= 0.034 mols

Mole \:  fraction =  \frac{ Moles \:  of \:  solute }{Total \:  number  \: of  \:  moles  \: of  \: soulte \:  and \:  solvent}

= \frac{  0.010 }{ 0.034}

= 0.29

0.29 \: P _{total} = 19 \:  kPa

P _{total} =  \frac{ 19  \: kPa }{0.29}

= 65.5 kPa

Therefore, the total pressure of the mixture is 65.5 kPa.

To know more about Dalton's law, refer to the below link:

brainly.com/question/14119417

#SPJ4

6 0
1 year ago
Can anyone answer this please
AlladinOne [14]

Answer:

where is the question

Explanation:

i dont see it

7 0
3 years ago
Suggest why CaO rather than MgO is used to dry ammonia.
V125BC [204]
Ca<span>2+</span> is less electro-positive than Mg2+. Therefore, CaO is less ionic than MgO. and in turn means that the O in CaO is more like O<span>2<span>– will react with H in H2O more so than O2- of MgO, because it is more ionic means O is strongly bonded to Mg compare to Ca</span></span>
5 0
3 years ago
A smaple of 1cm cuvette gives an absorbance reading of 0.558. if they absorptivity for this sample is 15000l/(mol.cm), what is t
Mazyrski [523]
To solve this problem, we use Beer's Law: A= ε.l.c
A is the absorbance- 0,558
<span>ε is</span> the molar absorptivity- is <span>15000 </span><span><span>L⋅mol-1</span><span>cm-1</span></span>
<span>l is </span>the length of the cuvette- 1 cm
<span>c is</span> the molar concentration

Applying the formula,
0,558= 15000 x 1 x c
0,558/15000= c
c= <span>3.72×<span>10⁻⁵ </span> <span>mol⋅L<span>⁻¹</span></span></span>
<span />
3 0
3 years ago
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