Answer:
add 6 unit tiles
Step-by-step explanation:
The square is completed when the algebra tile grid pattern is a square. This one will be a square when 6 more unit tiles are added to fill the empty spaces at the bottom right.
Hi there!
To find x, you would need to use the inverse of subtraction (addition) and inverse of division (multiplication), since you'd need to isolate x to one side of the equation to set x equal to a number.
Hope this helps!
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)
So the value of the element in the position 
is 15
So the value of the element in the position 
is 14
Then with these two values you can determinate the result matrix.
Note that if you simply reflected it and dilated it, it would be too far to the left
note that the distances bewteen the axises in image 1 were 1 and 3in image 3,the distances are 2 and 6
seems to be 3 times
so it's the 90 counterclockwise rotation and dilation by scale factor of 3
answer is last one
Answer:
it is the equation which you have to solve.
