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Ludmilka [50]
3 years ago
7

The nighttime and daytime temperatures on Mercury are 13 K and 683 K respectively. The melting point and boiling point of sulfur

is 246°F and 832°F. Which of the following statements is true? On Mercury sulfur exists
a. only in the liquid state.
b. only in the solid state.
c. as both a liquid and a gas.
d. as both a liquid and a solid
Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

Converting Fahrenheit into kelvin as follows.

           \frac{5}{9} \times (^{o}F - 32) + 273.15

So, 246^{o}F will be converted into kelvin as follows.

            \frac{5}{9} \times (246^{o}F - 32) + 273.15

                = 392.039 K

Also, 832^{o}F will be converted into kelvin as follows.

             \frac{5}{9} \times (832^{o}F - 32) + 273.15                                      

                = 717.594 K

As 13 K is the temperature at night time. So, it means sulfur will exist as a solid at this time because melting point of sulfur is 392.039 K.

Whereas 683 K is the temperature during day time. Hence, it means sulfur will exist in liquid state because its boiling point is 717.594 K.

Thus, we can conclude that on mercury, sulfur exists as both a liquid and a solid.

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Answer:

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Explanation:

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Note: H₂SO₄ is one of seven strong acids that you should try to memorize.

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3 years ago
Which spectroscopic tool would be best for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane?
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1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

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Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

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5 0
1 year ago
Balance the equation below and use it to answer this question:
Svet_ta [14]

Answer:

2H2 + O2 -----> 2H2O

Not sure about the second question though.

8 0
3 years ago
What is the mass of six of these marbles? What is the volume? What is the<br> density?
chubhunter [2.5K]

Answer:

All right. So let's calculate the density of a glass marble. Remember that the formula for density is mass over volume. So if I know that the masses 18.5 g. And I know that the um volume is 6.45 cubic centimeters. I can go ahead and answer this to three significant figures. So it's going to be 2.87 grams per cubic centimeter. Okay, that's our density. Now, density is an intensive process. Okay. We're an intensive property. I really should say. It doesn't depend on how much you have. Mhm. If I have one marble, its density is going to be 2.87 g per cubic centimeter. If I have two marbles, the density will be the same because I'll double the mass and I'll also double the volume. So when I divide them I'll get the same number. Okay, that's what makes it an intensive property. No matter how many marbles I have, they'll have the same density. Mass though is not an intensive property. So if I have six marbles and I want to know what the massive six marbles is. Well, I know the mass of each marble is 18.5 g. So the mass of six marbles Is going to be 100 11 g. Because mass is an extensive property. It depends on how much you have. If I change the number of marbles, I'm going to change the mass. That's an extensive property. All right. So we've calculated the density. We've calculated the mass and then what happens to the density of one marble compared to six marbles as we mentioned before. Since densities and intensive property, the densities will be the same, no matter how may.

Explanation:

5 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
3 years ago
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