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Andre45 [30]
1 year ago
10

A treasure chest is full of coins. The chest has a volume of 2.25L. The coins have a combined mass of 48kg. Calculate the densit

y of the coins to determine which metal they’re made of. Which metal are they?
a. Silver: 10.5 g/mL
b. Lead: 11.3 g/mL
c. Bronze: 8.7 g/mL
d. Gold: 19.3 g/mL
Chemistry
1 answer:
Softa [21]1 year ago
8 0

The density of the coin, given the data from the question is 21.33 g/mL.

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to determine the density of the coin</h3>

From the question given above, the following data were obtained:

  • Volume of coin = 2.25 L = 2.25 × 1000 = 2250 mL
  • Mass of coin = 48 Kg = 48 × 1000 = 48000 g
  • Density of coin =?

Density = mass / volume

Density = 48000 / 2250

Density = 21.33 g/mL

<h3>How to determine the metal</h3>

The density of the coin obtained, given the data from the question is 21.33 g/mL

Considering the options given, the density of the metal is not specified.

Learn more about density:

brainly.com/question/952755

#SPJ1

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The pictured compound has which of the following bonds?
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Answer: There are C - C  bonds and C - H bonds.

trust me! I took a test with this question and got 100! :)

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Consider the ions of potassium (K) and sulfur (S), Write chemical formulas for all possible ionic compounds involving these ions
attashe74 [19]

The compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

<h3>What is an ionic compound?</h3>

An ionic compound is a commpound that is composed of ions. Let us note that ionic compounds are always such that the sum of the charges on the ions is zero.

Hence, the compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

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4 0
2 years ago
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3. Balance each of the following redox reactions in the listed aqueous environment. (4 pts each, 8 pts total) Crs)NO3 (a) Cr (a)
GrogVix [38]

Explanation:

(a)   The given reaction equation is as follows.

        Cr(s) + NO^{-}_{3}(aq) \rightarrow Cr^{3+}(aq) + NO(g) (acidic)

So, here the reduction and oxidation-half reactions will be as follows.

Oxidation-half reaction: Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-}

Reduction-half-reaction: NO^{-}_{3} + 3e^{-}(aq) \rightarrow NO(g)

As total charge present on reactant side is -1 and total charge present on product side is +3. And, since it is present in aqueous medium. Hence, we will balance the charge for this reaction equation as follows.

      Cr(s) + NO^{-}_{3}(aq) + 4H^{+}(aq) \rightarrow Cr^{3+}(aq) + NO(g) + 2H_{2}O(l) (acidic)

(b)   The given reaction equation is as follows.

        HCO^{-}_{3}(aq) + Ag(s) + NH_{3}(aq) \rightarrow H_{2}CO(aq) + Ag(NH_{3})^{+}_{2}(aq) (basic)

So, here the reduction and oxidation-half reactions will be as follows.

Reduction-half reaction: HCO^{-}_{3}(aq) + 4e^{-} \rightarrow H_{2}CO(aq)

Oxidation-half reaction: Ag(s) \rightarrow Ag(NH_{3})^{+}_{2}(aq) + 1e^{-}

Hence, to balance the number of electrons in this equation we multiply it by 4 as follows.

      4Ag(s) \rightarrow 4Ag(NH_{3})^{+}_{2}(aq) + 4e^{-}

Therefore, balancing the whole reaction equation in the basic medium as follows.

      H_{2}CO(aq) + 4Ag(NH_{3})^{+}_{2}(aq) + 5OH^{-}(aq) \rightarrow HCO^{-}_{3}(aq) + 4Ag(s) + 8NH_{3}(aq) + 3H_{2}O(l)

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3 years ago
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DaniilM [7]
The presence of enzymes
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4 years ago
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Write the chemical symbol for the ion<br> with 33 protons and 36 electrons
Rashid [163]
  • We cannot change protons of any element
  • So the atomic number is 33
  • The element is Arsenic(As)

Now here is 36 electrons so it's. tri cation.

Symbol

\\ \tt\hookrightarrow As^{3+}

5 0
2 years ago
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