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weqwewe [10]
3 years ago
12

This drug is often prescribed by psychiatrists and family practice physicians for patients who can't fall asleep. A. Halcion B.

Motrin C. Cafergot D. Codeine
Chemistry
1 answer:
nika2105 [10]3 years ago
5 0
B I tjinksjwkzosmznqosnsnw
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How many Electrons, Neutrons & Protons do
EastWind [94]

Answer:

sodium

protons:11

neutrons:12

electrons:11

nitrogen

protons:7

neutrons:7

electrons:7

6 0
3 years ago
Read 2 more answers
Which elements have the most similar chemical properties?
Mumz [18]

Answer: K and Na

Explanation:

Potassium and Sodium have a chemical symbol of K and Na respectively.

They have similar chemical properties because both

- have only one valence electron,

- form univalent positive ion when they donate their lone outermost electron as shown below

Na --> Na+ + e-

K --> K+ + e-

- are good reducing agents

- react with cold water vigorously to liberate hydrogen gas and form alkalis, so they are known as alkali metals.

- K and Na are placed in Group 1 of the periodic table.

Thus, unlike the other pairs given, K and Na, have the most similar chemical properties

6 0
3 years ago
A solution
Gelneren [198K]
A solution <span>has a uniform composition and is only able to be separated by chemical means.</span>
4 0
3 years ago
If the concentration of nucleophile increases does the reaction go faster
Kay [80]
Depends on the situation. If the nucleophile is already in excess, then no the reaction will not occur faster 

4 0
3 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
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