Question

When 1 mole of bacl2 is dissolved in water it releases-8.67 kj/mil of energy. calculate h when 10.3 g of barium chloride is dissolved to make a 1.00 l solution

Answer 1

An inorganic substance with the formula BaCl2 is barium chloride. It is one of the most popular barium salts that dissolve in water. Like the majority of other water-soluble barium salts, it is white, extremely hazardous, and gives flames a yellow-green tint.

When 1 mole of bacl2 is dissolved in water it releases-8.67 kj/mil of energy. calculate h when 10.3 g of barium chloride is dissolved to make a 1.00 l solution

In water, barium chloride is very soluble (as is the case with most ionic salts). In its dissolved condition, it is known to split into barium cations and chloride anions.

Let's first determine the total amount of CL- ions.

=> When HCl dissociates, one mol will produce H+ and one mol will produce CL-. Thus, . 2 moles yields. 2 mol CL-

=> One mole of Bacl2 will dissociate into one mole of Ba2+ and two moles of CL-. Therefore, 0.1 mol will result. two moles CL-

Hence, there are mols of CL- in total.

2+.2 = .4

=> Molarity:

Total moles of solute divided by liters of solution gives the molarity, M.

= .4/.5 = 0.8 M

As a result, 0.8 M is the molarity of CL- in solution.

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Answer 2

Barium chloride is an inorganic compound with the formula BaCl2. This is one of the most regularly used barium salts that dissolve in water.

Therefore, the molarity of CL- in solution is 0.8 M.

What is BaCl2?

It is white, very dangerous, and tints flames yellow-green, like most other water-soluble barium salts.

8.67 kj/mil of energy is released when 1 mole of bacl2 dissolves in water. When 10.3 g of barium chloride dissolve in 1.00 l of solution, determine h.

Barium chloride is extremely soluble in water (as is the case with most ionic salts). It is known to separate into barium cations and chloride anions when dissolved.

What is the calculation of the above problem?

One mol of H+ and one mol of CL- are produced when HCl dissociates. As a result, 2 moles form. In order to produce 1 mol Ba2+ and 1 mol CL-, 1 mol Bacl2 dissociates into 1 mol Ba2+ and 2 mol CL-. As a result, 0.1 mol will be produced.

Thus, the total amount of CL- is mols.

By dividing the total moles of the solute by the volume of the solution, 2+.2 =.4 s =.4/.5 = 0.8 M, the molarity, M, is determined.

Therefore, the molarity of CL- in solution is 0.8 M.

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