Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Answer:
D:315
Step-by-step explanation:
6x7 and then divide by 2 = 21+21 =42 13x7= 91x3= 273+ 42= 315
Answer:
2x + 4y =8
substitute 0 for x
2 (0) + 4y = 8
0 +4y = 8
subtract 0 from both sides
-0 +4y =8 - 0
4y = 8
Divide both sides by 4
Y = 2
Step-by-step explanation:
Answer:
no solution
Step-by-step explanation:
hello
![6(x+5)=6x+11\\ 6x+30=6x+11\\ 30=11](https://tex.z-dn.net/?f=6%28x%2B5%29%3D6x%2B11%5C%5C%3C%3D%3E%206x%2B30%3D6x%2B11%5C%5C%3C%3D%3E%2030%3D11)
this is always false so there is no solution