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8_murik_8 [283]

4 years ago

12

In the diagram to the left, A man pushes two creates, each with mass 50 kg. To the right with a force of 200 N. How fast will th

e accelerate

1 answer:

Alekssandra [29.7K]4 years ago

3 0

Answer:

sorry no diagram is comin' in my phone

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Sally's mass on Earth is 50 kg. What is her weight on Earth?

Anarel [89]

Answer490N:

Explanation:

8 0

3 years ago

Help for physical science u4 limiting reactants

Yuliya22 [10]

The reactants are on the left and the products are on the right of the equation

3 0

4 years ago

At 19°C, a rod is exactly 19.11 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 280°C, where the r

Ratling [72]

Answer:

$\alpha = 4.12 \times 10^{-5} per Degree C$

Explanation:

As we know that when we increase the temperature of the rod and the ruler then in that case there will be change in the length of the both.

Due to this the ruler measurement is different from actual length of the rod

So by thermal expansion we know that

$L = L_o(1 +\alpha \Delta T)$

$L = 19.11 (1 + \alpha(280 - 19))$

$L = 19.11(1 + 261\alpha)$

Now for length of unit division of steel scale

$1 unit = 1( 1 + \alpha_s \Delta T)$

$1 unit = (1 + (11 \times 10^{-6})(280 - 19))$

$1 unit = 1.0029$

now the measured length from the scale is given as

$L_{measured} = \frac{L}{1.0029}$

$L_{measured} = \frac{19.11(1 + 261\alpha)}{1.0029}$

$19.26 = \frac{19.11(1 + 261\alpha)}{1.0029}$

$\alpha = 4.12 \times 10^{-5} per Degree C$

8 0

3 years ago

Harmonics problem. A square wave of frequency f contains harmonics (sine waves) at f, 3f, 5f, 7f, ... . Suppose a system respond

ira [324]

Answer:

B

Explanation:

A square of frequency of consists of the infinite sum of sine waves, whose frequencies are the odd multiples of the main frequency f i.e f, 3f,5f, 7f, ... . Given that the range of frequencies, to which the system responds is 20-40 kHz, for a square wave of frequency 10kHz we need to look for the harmonics whose frequencies are in the systems' respond range, which are the harmonics of 20, 30 and 40 kHz

4 0

3 years ago

A car of mass m, traveling at constant speed, rides over the top of a round hill. How do the normal force of the road on the car

dybincka [34]

Answer:

The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is <em>option B</em>.

Explanation:

Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:

At the top of a round hill

$Normal force = Gravitational force - centripetal force$

At the foot of a round hill

$Normal Force = centripetal force + Gravitational force$

4 0

4 years ago