Charges added to a CONDUCTOR will immediately spread throughout the body.
Answer:
4363.3231 feets²
Explanation:
Given that :
Distance, r = 50 ft
θ = 200°
The arc length of area covered :
Arc length = θ/360° * πr²
Arc length = (200/360) * 50 ft ^2 * π
Arc length = 0.5555555 * 2500 * π
Arc length = 4363.3231 feets²
Answer:
1.2 g/cm³
Explanation:
From the question given above, the following data were obtained:
Mass of solid = 180 g
Length (L) of solid = 10 cm
Width (W) of solid = 5 cm
Height (H) of solid = 3 cm
Density of solid =?
Next, we shall determine the volume of the solid. This can be obtained as follow:
Length (L) of solid = 10 cm
Width (W) of solid = 5 cm
Height (H) of solid = 3 cm
Volume (V) of solid =?
V = L× W × H
V = 10 × 5 × 3
V = 150 cm³
Finally, we shall determine the density of the solid. This can be obtained as follow:
Mass of solid = 180 g
Volume of solid = 150 cm³
Density of solid =?
Density = mass / volume
Density = 180 g / 150 cm³
Density of solid = 1.2 g/cm³
Cathode rays are negatively charged
Explanation:
Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.
Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.
One notable one was that he observed that the rays deflected towards the positively charged plate.
Since unlike poles attract then he concluded that the cathode rays were negatively charged.
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