Answer:
[2(p + 1)]/q
Step-by-step explanation:
logx 2 = p
logx 7 = q
log7 4x² = log7 (2x)²
= (logx (2x)²)/(logx 7)
= (2 logx 2x)/(logx 7)
= (2 logx 2 + 2 logx x)/(logx 7)
= (2p + 2)/q
= [2(p + 1)]/q
If the circle is at the origin and (0,4) is a point on the circle then the radius of the circle is:
r^2=0^2+4^2
r^2=16
r=4
so we can check that the other point is four units from the origin and thus also on the circle...
d^2=2^2+6^2
d^2=4+36
d^2=40
since d^2>r^2, (2,6) is outside the circle...
Answer: 16312.5
Step-by-step explanation:
That took a lot of time. There you go.
Trevor’s estimate is UNDERestimate because 8*6 is 48 and 8.33*6.2 = 51.646
